304 North Cardinal St.
Dorchester Center, MA 02124

# Remove Element LeetCode Solution

## Problem – Remove Element LeetCode Solution

Given an integer array `nums` and an integer `val`, remove all occurrences of `val` in `nums` in-place. The relative order of the elements may be changed.

Since it is impossible to change the length of the array in some languages, you must instead have the result be placed in the first part of the array `nums`. More formally, if there are `k` elements after removing the duplicates, then the first `k` elements of `nums` should hold the final result. It does not matter what you leave beyond the first `k` elements.

Return `k` after placing the final result in the first `k` slots of `nums`.

Do not allocate extra space for another array. You must do this by modifying the input array in-place with O(1) extra memory.

Custom Judge:

The judge will test your solution with the following code:

``````int[] nums = [...]; // Input array
int val = ...; // Value to remove
int[] expectedNums = [...]; // The expected answer with correct length.
// It is sorted with no values equaling val.

int k = removeElement(nums, val); // Calls your implementation

assert k == expectedNums.length;
sort(nums, 0, k); // Sort the first k elements of nums
for (int i = 0; i < actualLength; i++) {
assert nums[i] == expectedNums[i];
}
``````

If all assertions pass, then your solution will be accepted.

Example 1:

``````Input: nums = [3,2,2,3], val = 3
Output: 2, nums = [2,2,_,_]
Explanation: Your function should return k = 2, with the first two elements of nums being 2.
It does not matter what you leave beyond the returned k (hence they are underscores).``````

Example 2:

``````Input: nums = [0,1,2,2,3,0,4,2], val = 2
Output: 5, nums = [0,1,4,0,3,_,_,_]
Explanation: Your function should return k = 5, with the first five elements of nums containing 0, 0, 1, 3, and 4.
Note that the five elements can be returned in any order.
It does not matter what you leave beyond the returned k (hence they are underscores).``````

Constraints:

• `0 <= nums.length <= 100`
• `0 <= nums[i] <= 50`
• `0 <= val <= 100`

### Remove Element LeetCode Solution in Python

``````def removeElement(self, nums, val):
i = 0
for x in nums:
if x != val:
nums[i] = x
i += 1
return i
``````

### Remove Element LeetCode Solution in Java

``````public int removeElement(int[] A, int elem) {
int m = 0;
for(int i = 0; i < A.length; i++){

if(A[i] != elem){
A[m] = A[i];
m++;
}
}

return m;
}
``````

### Remove Element LeetCode Solution in C++

``````int removeElement(vector<int>& nums, int val) {
int cnt = 0;
for(int i = 0 ; i < nums.size() ; ++i) {
if(nums[i] == val)
cnt++;
else
nums[i-cnt] = nums[i];
}
return nums.size()-cnt;
}
``````
##### Remove Element LeetCode Solution Review:

In our experience, we suggest you solve this Remove Element LeetCode Solution and gain some new skills from Professionals completely free and we assure you will be worth it.

If you are stuck anywhere between any coding problem, just visit Queslers to get the Remove Element LeetCode Solution

Find on LeetCode

##### Conclusion:

I hope this Remove Element LeetCode Solution would be useful for you to learn something new from this problem. If it helped you then don’t forget to bookmark our site for more Coding Solutions.

This Problem is intended for audiences of all experiences who are interested in learning about Data Science in a business context; there are no prerequisites.

Keep Learning!

More Coding Solutions >>

LeetCode Solutions

Hacker Rank Solutions

CodeChef Solutions