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# Remove Linked List Elements LeetCode Solution

## Problem – Remove Linked List Elements LeetCode Solution

Given the `head` of a linked list and an integer `val`, remove all the nodes of the linked list that has `Node.val == val`, and return the new head.

Example 1:

``````Input: head = [1,2,6,3,4,5,6], val = 6
Output: [1,2,3,4,5]
``````

Example 2:

``````Input: head = [], val = 1
Output: []
``````

Example 3:

``````Input: head = [7,7,7,7], val = 7
Output: []
``````

Constraints:

• The number of nodes in the list is in the range `[0, 104]`.
• `1 <= Node.val <= 50`
• `0 <= val <= 50`

## Remove Linked List Elements LeetCode Solution in Java

``````public ListNode removeElements(ListNode head, int val) {
if (head == null) return null;
}
``````

## Remove Linked List Elements LeetCode Solution in Python

``````class Solution:
"""
:type val: int
:rtype: ListNode
"""

while current_node.next != None:
if current_node.next.val == val:
current_node.next = current_node.next.next
else:
current_node = current_node.next

``````

## Remove Linked List Elements LeetCode Solution in C++

``````class Solution {
public:
ListNode* removeElements(ListNode* head, int T) {
ListNode *dummy = new ListNode(-1, head), *prev = dummy;
prev = head;                       // just update prev node
else                                   // current node needs to be deleted
prev -> next = head -> next;       // just update next of prev to next of current so that current node is removed from list
return dummy -> next;
}
};
``````
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