Remove Nth Node From End of List LeetCode Solution

Problem – Remove Nth Node From End of List

Given the head of a linked list, remove the nth node from the end of the list and return its head.

Example 1:

Input: head = [1,2,3,4,5], n = 2
Output: [1,2,3,5]

Example 2:

Input: head = [1], n = 1
Output: []

Example 3:

Input: head = [1,2], n = 1
Output: [1]

Constraints:

• The number of nodes in the list is sz.
• 1 <= sz <= 30
• 0 <= Node.val <= 100
• 1 <= n <= sz

Remove Nth Node From End of List LeetCode Solution in Python

class Solution:
    def removeNthFromEnd(self, head: ListNode, n: int) -> ListNode:
        fast, slow = head, head
        for _ in range(n): fast = fast.next
        if not fast: return head.next
        while fast.next: fast, slow = fast.next, slow.next
        slow.next = slow.next.next
        return head

Remove Nth Node From End of List LeetCode Solution in Java

class Solution {
    public ListNode removeNthFromEnd(ListNode head, int n) {
        ListNode fast = head, slow = head;
        for (int i = 0; i < n; i++) fast = fast.next;
        if (fast == null) return head.next;
        while (fast.next != null) {
            fast = fast.next;
            slow = slow.next;
        }
        slow.next = slow.next.next;
        return head;
    }
}

Remove Nth Node From End of List LeetCode Solution in C++

class Solution {
public:
    ListNode* removeNthFromEnd(ListNode* head, int n) {
        ListNode *fast = head, *slow = head;
        for (int i = 0; i < n; i++) fast = fast->next;
        if (!fast) return head->next;
        while (fast->next) fast = fast->next, slow = slow->next;
        slow->next = slow->next->next;
        return head;
    }
};

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