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# Reverse Integer LeetCode Solution – Queslers

## Problem – Reverse Integer

Given a signed 32-bit integer `x`, return `x` with its digits reversed. If reversing `x` causes the value to go outside the signed 32-bit integer range `[-231, 231 - 1]`, then return `0`.

Assume the environment does not allow you to store 64-bit integers (signed or unsigned).

Example 1:

``````Input: x = 123
Output: 321``````

Example 2:

``````Input: x = -123
Output: -321``````

Example 3:

``````Input: x = 120
Output: 21``````

Constraints:

• `-231 <= x <= 231 - 1`

### Reverse Integer LeetCode Solution in Java

``````public int reverse(int x)
{
int result = 0;

while (x != 0)
{
int tail = x % 10;
int newResult = result * 10 + tail;
if ((newResult - tail) / 10 != result)
{ return 0; }
result = newResult;
x = x / 10;
}

return result;
}
``````

### Reverse Integer LeetCode Solution in Python

``````class Solution:
def reverse(self, x):
"""
:type x: int
:rtype: int
"""
sign = [1,-1][x < 0]
rst = sign * int(str(abs(x))[::-1])
return rst if -(2**31)-1 < rst < 2**31 else 0
``````

### Reverse Integer LeetCode Solution in C++

``````class Solution {
public:
int reverse(int x) {
int ans = 0;
while (x) {
int temp = ans * 10 + x % 10;
if (temp / 10 != ans)
return 0;
ans = temp;
x /= 10;
}
return ans;
}
};
``````
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