Reverse Linked List LeetCode Solution – Queslers

Problem – Reverse Linked List LeetCode Solution

Given the head of a singly linked list, reverse the list, and return the reversed list.

Example 1:

Input: head = [1,2,3,4,5]
Output: [5,4,3,2,1]

Example 2:

Input: head = [1,2]
Output: [2,1]

Example 3:

Input: head = []
Output: []

Constraints:

• The number of nodes in the list is the range [0, 5000].
• -5000 <= Node.val <= 5000

Reverse Linked List LeetCode Solution in Java

public ListNode reverseList(ListNode head) {
    /* iterative solution */
    ListNode newHead = null;
    while (head != null) {
        ListNode next = head.next;
        head.next = newHead;
        newHead = head;
        head = next;
    }
    return newHead;
}

public ListNode reverseList(ListNode head) {
    /* recursive solution */
    return reverseListInt(head, null);
}

private ListNode reverseListInt(ListNode head, ListNode newHead) {
    if (head == null)
        return newHead;
    ListNode next = head.next;
    head.next = newHead;
    return reverseListInt(next, head);
}

Reverse Linked List LeetCode Solution in Python

class Solution:
# @param {ListNode} head
# @return {ListNode}
def reverseList(self, head):
    prev = None
    while head:
        curr = head
        head = head.next
        curr.next = prev
        prev = curr
    return prev

Reverse Linked List LeetCode Solution in C++

class Solution {
public:
    ListNode* reverseList(ListNode* head) {
        ListNode *pre = new ListNode(0), *cur = head;
        pre -> next = head;
        while (cur && cur -> next) {
            ListNode* temp = pre -> next;
            pre -> next = cur -> next;
            cur -> next = cur -> next -> next;
            pre -> next -> next = temp;
        }
        return pre -> next;
    }
};

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