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# Reverse Linked List LeetCode Solution – Queslers

## Problem – Reverse Linked List LeetCode Solution

Given the `head` of a singly linked list, reverse the list, and return the reversed list.

Example 1:

``````Input: head = [1,2,3,4,5]
Output: [5,4,3,2,1]``````

Example 2:

``````Input: head = [1,2]
Output: [2,1]``````

Example 3:

``````Input: head = []
Output: []
``````

Constraints:

• The number of nodes in the list is the range `[0, 5000]`.
• `-5000 <= Node.val <= 5000`

### Reverse Linked List LeetCode Solution in Java

``````public ListNode reverseList(ListNode head) {
/* iterative solution */
ListNode newHead = null;
while (head != null) {
ListNode next = head.next;
}
}

public ListNode reverseList(ListNode head) {
/* recursive solution */
}

private ListNode reverseListInt(ListNode head, ListNode newHead) {
if (head == null)
ListNode next = head.next;
}
``````

### Reverse Linked List LeetCode Solution in Python

``````class Solution:
# @param {ListNode} head
# @return {ListNode}
prev = None
curr.next = prev
prev = curr
return prev
``````

### Reverse Linked List LeetCode Solution in C++

``````class Solution {
public:
ListNode* reverseList(ListNode* head) {
ListNode *pre = new ListNode(0), *cur = head;
pre -> next = head;
while (cur && cur -> next) {
ListNode* temp = pre -> next;
pre -> next = cur -> next;
cur -> next = cur -> next -> next;
pre -> next -> next = temp;
}
return pre -> next;
}
};
``````
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