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# Reverse String LeetCode Solution – Queslers

## Problem – Reverse String LeetCode Solution

Write a function that reverses a string. The input string is given as an array of characters `s`.

You must do this by modifying the input array in-place with `O(1)` extra memory.

Example 1:

``````Input: s = ["h","e","l","l","o"]
Output: ["o","l","l","e","h"]``````

Example 2:

``````Input: s = ["H","a","n","n","a","h"]
Output: ["h","a","n","n","a","H"]``````

Constraints:

• `1 <= s.length <= 105`
• `s[i]` is a printable ascii character.

### Reverse String LeetCode Solution in Java

``````public class Solution {
public String reverseString(String s) {
char[] word = s.toCharArray();
int i = 0;
int j = s.length() - 1;
while (i < j) {
char temp = word[i];
word[i] = word[j];
word[j] = temp;
i++;
j--;
}
return new String(word);
}
}
``````

### Reverse String LeetCode Solution in C++

``````class Solution {
public:
string reverseString(string s) {
int i = 0, j = s.size() - 1;
while(i < j){
swap(s[i++], s[j--]);
}

return s;
}
};``````

### Reverse String LeetCode Solution in Python

``````class Solution:
def reverseString(self, s):
for i in range(len(s)//2): s[i], s[-i-1] = s[-i-1], s[i]
``````
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