Reverse Words in a String III LeetCode Solution

Problem – Reverse Words in a String III

Given a string s, reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order.

Example 1:

Input: s = "Let's take LeetCode contest"
Output: "s'teL ekat edoCteeL tsetnoc"

Example 2:

Input: s = "God Ding"
Output: "doG gniD"

Constraints:

  • 1 <= s.length <= 5 * 104
  • s contains printable ASCII characters.
  • s does not contain any leading or trailing spaces.
  • There is at least one word in s.
  • All the words in s are separated by a single space.

Reverse Words in a String III LeetCode Solution in Python

def reverseWords(self, s):
    return ' '.join(s.split()[::-1])[::-1]

Reverse Words in a String III LeetCode Solution in C++

class Solution {
public:
    string reverseWords(string s) {
        for (int i = 0; i < s.length(); i++) {
            if (s[i] != ' ') {   // when i is a non-space
                int j = i;
                for (; j < s.length() && s[j] != ' '; j++) { } // move j to the next space
                reverse(s.begin() + i, s.begin() + j);
                i = j - 1;
            }
        }
        
        return s;
    }
};

Reverse Words in a String III LeetCode Solution in Java

public class Solution {
    public String reverseWords(String s) {
        char[] ca = s.toCharArray();
        for (int i = 0; i < ca.length; i++) {
            if (ca[i] != ' ') {   // when i is a non-space
                int j = i;
                while (j + 1 < ca.length && ca[j + 1] != ' ') { j++; } // move j to the end of the word
                reverse(ca, i, j);
                i = j;
            }
        }
        return new String(ca);
    }

    private void reverse(char[] ca, int i, int j) {
        for (; i < j; i++, j--) {
            char tmp = ca[i];
            ca[i] = ca[j];
            ca[j] = tmp;
        }
    }
}
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