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# Richest Customer Wealth LeetCode Solution

## Problem – Richest Customer Wealth LeetCode Solution

You are given an `m x n` integer grid `accounts` where `accounts[i][j]` is the amount of money the `i​​​​​​​​​​​th​​​​` customer has in the `j​​​​​​​​​​​th`​​​​ bank. Return the wealth that the richest customer has.

A customer’s wealth is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum wealth.

Example 1:

``````Input: accounts = [[1,2,3],[3,2,1]]
Output: 6
Explanation:
1st customer has wealth = 1 + 2 + 3 = 6
2nd customer has wealth = 3 + 2 + 1 = 6
Both customers are considered the richest with a wealth of 6 each, so return 6.
``````

Example 2:

``````Input: accounts = [[1,5],[7,3],[3,5]]
Output: 10
Explanation:
1st customer has wealth = 6
2nd customer has wealth = 10
3rd customer has wealth = 8
The 2nd customer is the richest with a wealth of 10.
``````

Example 3:

``````Input: accounts = [[2,8,7],[7,1,3],[1,9,5]]
Output: 17
``````

Constraints:

• `m == accounts.length`
• `n == accounts[i].length`
• `1 <= m, n <= 50`
• `1 <= accounts[i][j] <= 100`

### Richest Customer Wealth LeetCode Solution in Java

``````class Solution {
public int maximumWealth(int[][] accounts) {
int res = 0;
for(int i =0;i<accounts.length;i++){
int temp = 0;
for(int j = 0;j<accounts[i].length;j++){
temp+=accounts[i][j];
}
res = Math.max(res,temp);
}
return res;
}
}
``````

### Richest Customer Wealth LeetCode Solution in C++

``````class Solution {
public:
int maximumWealth(vector<vector<int>>& accounts) {
int res = 0;
for(int i =0;i<accounts.size();i++){
int temp = 0;
for(int j = 0;j<accounts[i].size();j++){
temp+=accounts[i][j];
}
res = max(res,temp);
}
return res;
}
};
``````

### Richest Customer Wealth LeetCode Solution in Python

``````    def maximumWealth(self, accounts):
return max(map(sum, accounts))
``````
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