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# Rising Temperature LeetCode Solution

## Problem – Rising Temperature LeetCode Solution

SQL Schema

Table: Weather

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| id            | int     |
| recordDate    | date    |
| temperature   | int     |
+---------------+---------+
id is the primary key for this table.
This table contains information about the temperature on a certain day.

Write an SQL query to find all dates’ Id with higher temperatures compared to its previous dates (yesterday).

Return the result table in any order.

The query result format is in the following example.

Example 1:

Input:
Weather table:
+----+------------+-------------+
| id | recordDate | temperature |
+----+------------+-------------+
| 1  | 2015-01-01 | 10          |
| 2  | 2015-01-02 | 25          |
| 3  | 2015-01-03 | 20          |
| 4  | 2015-01-04 | 30          |
+----+------------+-------------+
Output:
+----+
| id |
+----+
| 2  |
| 4  |
+----+
Explanation:
In 2015-01-02, the temperature was higher than the previous day (10 -> 25).
In 2015-01-04, the temperature was higher than the previous day (20 -> 30).

## Rising Temperature LeetCode Solution in MySQL

SELECT a.Id FROM Weather AS a, Weather AS b
WHERE DATEDIFF(a.Date, b.Date)=1 AND a.Temperature > b.Temperature

## Rising Temperature LeetCode Solution in MS SQL Server

SELECT w2.Id
FROM Weather w1
INNER JOIN Weather w2 ON DATEDIFF(day, w1.recordDate, w2.recordDate)=1 AND w2.Temperature > w1.Temperature

## Rising Temperature LeetCode Solution in Oracle

select t.id as ID
from (select w.id,
--   w.recorddate,
w.temperature as tt,
--  lag(w.recorddate, 1) over(order by w.recorddate) as dt,
w.recorddate - lag(w.recorddate, 1) over(order by w.recorddate) as dtmin,
lag(w.temperature, 1) over(order by w.recorddate) as tmp
from weather w) t
where dtmin = 1
and t.tt > t.tmp
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