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# Rotate Image LeetCode Solution – Queslers

## Problem – Rotate Image

You are given an `n x n` 2D `matrix` representing an image, rotate the image by 90 degrees (clockwise).

You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.

Example 1:

``````Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Output: [[7,4,1],[8,5,2],[9,6,3]]``````

Example 2:

``````Input: matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
Output: [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]``````

Constraints:

• `n == matrix.length == matrix[i].length`
• `1 <= n <= 20`
• `-1000 <= matrix[i][j] <= 1000`

### Rotate Image LeetCode Solution in Python

``````class Solution:
def rotate(self, A):
A[:] = zip(*A[::-1])``````

### Rotate Image LeetCode Solution in Java

``````public class Solution {
public void rotate(int[][] matrix) {
for(int i = 0; i<matrix.length; i++){
for(int j = i; j<matrix.length; j++){
int temp = 0;
temp = matrix[i][j];
matrix[i][j] = matrix[j][i];
matrix[j][i] = temp;
}
}
for(int i =0 ; i<matrix.length; i++){
for(int j = 0; j<matrix.length/2; j++){
int temp = 0;
temp = matrix[i][j];
matrix[i][j] = matrix[i][matrix.length-1-j];
matrix[i][matrix.length-1-j] = temp;
}
}
}
}
``````

### Rotate Image LeetCode Solution in C++

``````void rotate(vector<vector<int>>& matrix) {
int n = matrix.size();
int a = 0;
int b = n-1;
while(a<b){
for(int i=0;i<(b-a);++i){
swap(matrix[a][a+i], matrix[a+i][b]);
swap(matrix[a][a+i], matrix[b][b-i]);
swap(matrix[a][a+i], matrix[b-i][a]);
}
++a;
--b;
}
}
``````
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