Rotate Image LeetCode Solution – Queslers

Problem – Rotate Image

You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise).

You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.

Example 1:

Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Output: [[7,4,1],[8,5,2],[9,6,3]]

Example 2:

Input: matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
Output: [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]


  • n == matrix.length == matrix[i].length
  • 1 <= n <= 20
  • -1000 <= matrix[i][j] <= 1000

Rotate Image LeetCode Solution in Python

class Solution:
    def rotate(self, A):
        A[:] = zip(*A[::-1])

Rotate Image LeetCode Solution in Java

public class Solution {
    public void rotate(int[][] matrix) {
        for(int i = 0; i<matrix.length; i++){
            for(int j = i; j<matrix[0].length; j++){
                int temp = 0;
                temp = matrix[i][j];
                matrix[i][j] = matrix[j][i];
                matrix[j][i] = temp;
        for(int i =0 ; i<matrix.length; i++){
            for(int j = 0; j<matrix.length/2; j++){
                int temp = 0;
                temp = matrix[i][j];
                matrix[i][j] = matrix[i][matrix.length-1-j];
                matrix[i][matrix.length-1-j] = temp;

Rotate Image LeetCode Solution in C++

void rotate(vector<vector<int>>& matrix) {
        int n = matrix.size();
        int a = 0;
        int b = n-1;
            for(int i=0;i<(b-a);++i){
                swap(matrix[a][a+i], matrix[a+i][b]);
                swap(matrix[a][a+i], matrix[b][b-i]);
                swap(matrix[a][a+i], matrix[b-i][a]);
Rotate Image LeetCode Solution Review:

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