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# Shortest Impossible Sequence of Rolls LeetCode Solution

## Problem – Shortest Impossible Sequence of Rolls LeetCode Solution

You are given an integer array `rolls` of length `n` and an integer `k`. You roll a `k` sided dice numbered from `1` to `k``n` times, where the result of the `ith` roll is `rolls[i]`.

Return the length of the shortest sequence of rolls that cannot be taken from `rolls`.

sequence of rolls of length `len` is the result of rolling a `k` sided dice `len` times.

Note that the sequence taken does not have to be consecutive as long as it is in order.

Example 1:

``````Input: rolls = [4,2,1,2,3,3,2,4,1], k = 4
Output: 3
Explanation: Every sequence of rolls of length 1, [1], [2], [3], [4], can be taken from rolls.
Every sequence of rolls of length 2, [1, 1], [1, 2], ..., [4, 4], can be taken from rolls.
The sequence [1, 4, 2] cannot be taken from rolls, so we return 3.
Note that there are other sequences that cannot be taken from rolls.``````

Example 2:

``````Input: rolls = [1,1,2,2], k = 2
Output: 2
Explanation: Every sequence of rolls of length 1, [1], [2], can be taken from rolls.
The sequence [2, 1] cannot be taken from rolls, so we return 2.
Note that there are other sequences that cannot be taken from rolls but [2, 1] is the shortest.``````

Example 3:

``````Input: rolls = [1,1,3,2,2,2,3,3], k = 4
Output: 1
Explanation: The sequence [4] cannot be taken from rolls, so we return 1.
Note that there are other sequences that cannot be taken from rolls but [4] is the shortest.
``````

Constraints:

• `n == rolls.length`
• `1 <= n <= 105`
• `1 <= rolls[i] <= k <= 105`

### Shortest Impossible Sequence of Rolls LeetCode Solution in Java

``````    public int shortestSequence(int[] A, int k) {
int res = 1;
Set<Integer> s = new HashSet<>();
for (int a : A) {
if (s.size() == k) {
res++;
s.clear();
}
}
return res;
}
``````

### Shortest Impossible Sequence of Rolls LeetCode Solution in C++

``````    int shortestSequence(vector<int>& A, int k) {
int res = 1;
unordered_set<int> s;
for (int& a : A) {
s.insert(a);
if (s.size() == k) {
res++;
s.clear();
}
}
return res;
}
``````

### Shortest Impossible Sequence of Rolls LeetCode Solution in Python

``````    def shortestSequence(self, rolls, k):
res = 1
s = set()
for a in rolls:
if len(s) == k:
res += 1
s.clear()
return res
``````
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