Shortest Palindrome LeetCode Solution

Problem – Shortest Palindrome LeetCode Solution

You are given a string s. You can convert s to a palindrome by adding characters in front of it.

Return the shortest palindrome you can find by performing this transformation.

Example 1:

Input: s = "aacecaaa"
Output: "aaacecaaa"

Example 2:

Input: s = "abcd"
Output: "dcbabcd"

Constraints:

• 0 <= s.length <= 5 * 104
• s consists of lowercase English letters only.

Shortest Palindrome LeetCode Solution in Python

def shortestPalindrome(self, s):
    r = s[::-1]
    for i in range(len(s) + 1):
        if s.startswith(r[i:]):
            return r[:i] + s

Shortest Palindrome LeetCode Solution in Java

    int j = 0;
    for (int i = s.length() - 1; i >= 0; i--) {
        if (s.charAt(i) == s.charAt(j)) { j += 1; }
    }
    if (j == s.length()) { return s; }
    String suffix = s.substring(j);
    return new StringBuffer(suffix).reverse().toString() + shortestPalindrome(s.substring(0, j)) + suffix;

Shortest Palindrome LeetCode Solution in C++

class Solution {
public:
    string shortestPalindrome(string s) {
        string rev_s = s;
        reverse(rev_s.begin(), rev_s.end());
        string l = s + "#" + rev_s;
        
        vector<int> p(l.size(), 0);
        for (int i = 1; i < l.size(); i++) {
            int j = p[i - 1];
            while (j > 0 && l[i] != l[j])
                j = p[j - 1];
            p[i] = (j += l[i] == l[j]);
        }
        
        return rev_s.substr(0, s.size() - p[l.size() - 1]) + s;
    }
};

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