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# Simplify Path LeetCode Solution

## Problem – Simplify Path LeetCode Solution

Given a string `path`, which is an absolute path (starting with a slash `'/'`) to a file or directory in a Unix-style file system, convert it to the simplified canonical path.

In a Unix-style file system, a period `'.'` refers to the current directory, a double period `'..'` refers to the directory up a level, and any multiple consecutive slashes (i.e. `'//'`) are treated as a single slash `'/'`. For this problem, any other format of periods such as `'...'` are treated as file/directory names.

The canonical path should have the following format:

• The path starts with a single slash `'/'`.
• Any two directories are separated by a single slash `'/'`.
• The path does not end with a trailing `'/'`.
• The path only contains the directories on the path from the root directory to the target file or directory (i.e., no period `'.'` or double period `'..'`)

Return the simplified canonical path.

Example 1:

``````Input: path = "/home/"
Output: "/home"
Explanation: Note that there is no trailing slash after the last directory name.
``````

Example 2:

``````Input: path = "/../"
Output: "/"
Explanation: Going one level up from the root directory is a no-op, as the root level is the highest level you can go.
``````

Example 3:

``````Input: path = "/home//foo/"
Output: "/home/foo"
Explanation: In the canonical path, multiple consecutive slashes are replaced by a single one.
``````

Constraints:

• `1 <= path.length <= 3000`
• `path` consists of English letters, digits, period `'.'`, slash `'/'` or `'_'`.
• `path` is a valid absolute Unix path.

## Simplify Path LeetCode Solution in Java

``````public String simplifyPath(String path) {
Set<String> skip = new HashSet<>(Arrays.asList("..",".",""));
for (String dir : path.split("/")) {
if (dir.equals("..") && !stack.isEmpty()) stack.pop();
else if (!skip.contains(dir)) stack.push(dir);
}
String res = "";
for (String dir : stack) res = "/" + dir + res;
return res.isEmpty() ? "/" : res;
}
``````

## Simplify Path LeetCode Solution in C++

``````string simplifyPath(string path) {
string res, tmp;
vector<string> stk;
stringstream ss(path);
while(getline(ss,tmp,'/')) {
if (tmp == "" or tmp == ".") continue;
if (tmp == ".." and !stk.empty()) stk.pop_back();
else if (tmp != "..") stk.push_back(tmp);
}
for(auto str : stk) res += "/"+str;
return res.empty() ? "/" : res;
}
``````

## Simplify Path LeetCode Solution in Python

``````class Solution(object):
def simplifyPath(self, path):
places = [p for p in path.split("/") if p!="." and p!=""]
stack = []
for p in places:
if p == "..":
if len(stack) > 0:
stack.pop()
else:
stack.append(p)
return "/" + "/".join(stack)
``````
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