Physical Address
304 North Cardinal St.
Dorchester Center, MA 02124
Given an integer array nums
, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. You can return the answer in any order.
You must write an algorithm that runs in linear runtime complexity and uses only constant extra space.
Example 1:
Input: nums = [1,2,1,3,2,5]
Output: [3,5]
Explanation: [5, 3] is also a valid answer.
Example 2:
Input: nums = [-1,0]
Output: [-1,0]
Example 3:
Input: nums = [0,1]
Output: [1,0]
Constraints:
2 <= nums.length <= 3 * 104
-231 <= nums[i] <= 231 - 1
nums
will appear twice, only two integers will appear once.class Solution
{
public:
vector<int> singleNumber(vector<int>& nums)
{
// Pass 1 :
// Get the XOR of the two numbers we need to find
int diff = accumulate(nums.begin(), nums.end(), 0, bit_xor<int>());
// Get its last set bit
diff &= -diff;
// Pass 2 :
vector<int> rets = {0, 0}; // this vector stores the two numbers we will return
for (int num : nums)
{
if ((num & diff) == 0) // the bit is not set
{
rets[0] ^= num;
}
else // the bit is set
{
rets[1] ^= num;
}
}
return rets;
}
};
public class Solution {
public int[] singleNumber(int[] nums) {
// Pass 1 :
// Get the XOR of the two numbers we need to find
int diff = 0;
for (int num : nums) {
diff ^= num;
}
// Get its last set bit
diff &= -diff;
// Pass 2 :
int[] rets = {0, 0}; // this array stores the two numbers we will return
for (int num : nums)
{
if ((num & diff) == 0) // the bit is not set
{
rets[0] ^= num;
}
else // the bit is set
{
rets[1] ^= num;
}
}
return rets;
}
}
class Solution:
def singleNumber(self, nums):
s = reduce(xor, nums)
nz = s & (s-1) ^ s
num1 = reduce(xor, filter(lambda n: n & nz, nums))
return(num1, s ^ num1)
In our experience, we suggest you solve this Single Number III LeetCode Solution and gain some new skills from Professionals completely free and we assure you will be worth it.
If you are stuck anywhere between any coding problem, just visit Queslers to get the Single Number III LeetCode Solution
I hope this Single Number III LeetCode Solution would be useful for you to learn something new from this problem. If it helped you then don’t forget to bookmark our site for more Coding Solutions.
This Problem is intended for audiences of all experiences who are interested in learning about Data Science in a business context; there are no prerequisites.
Keep Learning!
More Coding Solutions >>