**Physical Address**

304 North Cardinal St.

Dorchester Center, MA 02124

Six friends go on a trip and are looking for accommodation. After looking for hours, they find a hotel which offers two types of rooms — double rooms and triple rooms. A double room costs Rs. *X*, while a triple room costs Rs. *Y*.

The friends can either get three double rooms or get two triple rooms. Find the minimum amount they will have to pay to accommodate all six of them.

- The first line contains a single integer
*T*– the number of test cases. Then the test cases follow. - The first and only line of each test case contains two integers
*X*and*Y*– the cost of a double room and the cost of a triple room.

For each testcase, output the minimum amount required to accommodate all the six friends.

- 1≤
*T*≤100 - 1≤
*X*<*Y*≤100

```
Input: 3
10 15
6 8
4 8
Output: 30
16
12
```

**Test case 1:** The friends can take three double rooms and thus pay a total of Rs. 30.

**Test case 2:** The friends can take two triple rooms and thus pay a total of Rs. 16.

**Test case 3:** The friends can take three double rooms and thus pay a total of Rs. 12

```
#include <iostream>
using namespace std;
int main() {
int t,x,y;
cin>>t;
while(t--){
cin>>x>>y;
cout<<min((3*x),(2*y))<<endl;
}
return 0;
}
```

```
#no. of inputs
t = int(input())
#program
for _ in range(t):
# rates of rooms
x,y= map(int,input().split())
a = x*3
b = y*2
if a <= b:
print(a)
else:
print(b)
```

```
import java.util.*;
import java.lang.*;
import java.io.*;
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int t = sc.nextInt();
while(t-- > 0){
int x = sc.nextInt();
int y = sc.nextInt();
int db = x * 3 ;
int tr = y * 2 ;
if(db >= tr){
System.out.println(tr);
}
else {
System.out.println(db);
}
}
}
}
```

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