304 North Cardinal St.
Dorchester Center, MA 02124

# Sliding Window Maximum LeetCode Solution

## Problem – Sliding Window Maximum

You are given an array of integers `nums`, there is a sliding window of size `k` which is moving from the very left of the array to the very right. You can only see the `k` numbers in the window. Each time the sliding window moves right by one position.

Return the max sliding window.

Example 1:

``````Input: nums = [1,3,-1,-3,5,3,6,7], k = 3
Output: [3,3,5,5,6,7]
Explanation:
Window position                Max
---------------               -----
[1  3  -1] -3  5  3  6  7       3
1 [3  -1  -3] 5  3  6  7       3
1  3 [-1  -3  5] 3  6  7       5
1  3  -1 [-3  5  3] 6  7       5
1  3  -1  -3 [5  3  6] 7       6
1  3  -1  -3  5 [3  6  7]      7
``````

Example 2:

``````Input: nums = , k = 1
Output: ``````

Constraints:

• `1 <= nums.length <= 105`
• `-104 <= nums[i] <= 104`
• `1 <= k <= nums.length`

### Sliding Window Maximum LeetCode Solution in Java

``````public int[] maxSlidingWindow(int[] a, int k) {
if (a == null || k <= 0) {
return new int;
}
int n = a.length;
int[] r = new int[n-k+1];
int ri = 0;
// store index
Deque<Integer> q = new ArrayDeque<>();
for (int i = 0; i < a.length; i++) {
// remove numbers out of range k
while (!q.isEmpty() && q.peek() < i - k + 1) {
q.poll();
}
// remove smaller numbers in k range as they are useless
while (!q.isEmpty() && a[q.peekLast()] < a[i]) {
q.pollLast();
}
// q contains index... r contains content
q.offer(i);
if (i >= k - 1) {
r[ri++] = a[q.peek()];
}
}
return r;
}
``````

### Sliding Window Maximum LeetCode Solution in C++

``````class Solution {
public:
vector<int> maxSlidingWindow(vector<int>& nums, int k) {
deque<int> dq;
vector<int> ans;
for (int i=0; i<nums.size(); i++) {
if (!dq.empty() && dq.front() == i-k) dq.pop_front();
while (!dq.empty() && nums[dq.back()] < nums[i])
dq.pop_back();
dq.push_back(i);
if (i>=k-1) ans.push_back(nums[dq.front()]);
}
return ans;
}
};
``````

### Sliding Window Maximum LeetCode Solution in Python

``````def maxSlidingWindow(self, nums, k):
d = collections.deque()
out = []
for i, n in enumerate(nums):
while d and nums[d[-1]] < n:
d.pop()
d += i,
if d == i - k:
d.popleft()
if i >= k - 1:
out += nums[d],
return out``````
##### Sliding Window Maximum LeetCode Solution Review:

In our experience, we suggest you solve this Sliding Window Maximum LeetCode Solution and gain some new skills from Professionals completely free and we assure you will be worth it.

If you are stuck anywhere between any coding problem, just visit Queslers to get the Sliding Window Maximum LeetCode Solution

Find on LeetCode

##### Conclusion:

I hope this Sliding Window Maximum LeetCode Solution would be useful for you to learn something new from this problem. If it helped you then don’t forget to bookmark our site for more Coding Solutions.

This Problem is intended for audiences of all experiences who are interested in learning about Data Science in a business context; there are no prerequisites.

Keep Learning!

More Coding Solutions >>

LeetCode Solutions

Hacker Rank Solutions

CodeChef Solutions