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SnackUp CodeChef Solution
Problem -SnackUp CodeChef Solution
This website is dedicated for CodeChef solution where we will publish right solution of all your favourite CodeChef problems along with detailed explanatory of different competitive programming concepts and languages.
SnackUp CodeChef Solution in C++14
#include <iostream>
#define ll long long int
using namespace std;
int main()
{ ll t; cin >> t;
// seive();
while (t--) {
ll n; cin >> n;
cout<<n<<endl;
for (ll j = 0; j <n; j++)
{
cout<<n<<endl;
for (ll i = 0; i < n; i++)
{
cout<<i+1<<" "<<((i+j)%n)+1<<" "<<((i+j+1)%n)+1<<endl;
}
}
}
return 0;}SnackUp CodeChef Solution in PYTH 3
def soln(n):
arr = [(i, i+1) for i in range(1, n)]
arr.append((1, n))
print(n)
for i in range(n):
print(n)
for j in range(n):
print(j+1, *arr[(i+j)%n])
for _ in range(int(input())):
n = int(input())
soln(n)SnackUp CodeChef Solution in C
#include <stdio.h>
int main(void) {
// your code goes here
int i,t;
scanf("%d",&t);
while(t--){
int n;
scanf("%d",&n);
printf("%d\n",n);
for(i=1;i<=n;i++){
printf("%d\n",n);
for(int j=1;j<=n;j++){
int x=j+i-1 , y=j+i;
if(x>n && x%n!=0)
{
x=x%n;
}
else if(x%n==0){
x=n;
}
if(y>n && y%n!=0){
y=y%n;
}
else if(y%n==0){
y=n;
}
printf("%d %d %d\n",j,x,y);
}
}
}
return 0;
}
SnackUp CodeChef Solution in JAVA
/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{ static class FastReader{
BufferedReader br;
StringTokenizer st;
public FastReader(){
br=new BufferedReader(new InputStreamReader(System.in));
}
String next(){
while(st==null || !st.hasMoreTokens()){
try {
st=new StringTokenizer(br.readLine());
} catch (IOException e) {
e.printStackTrace();
}
}
return st.nextToken();
}
int nextInt(){
return Integer.parseInt(next());
}
long nextLong(){
return Long.parseLong(next());
}
double nextDouble(){
return Double.parseDouble(next());
}
String nextLine(){
String str="";
try {
str=br.readLine().trim();
} catch (Exception e) {
e.printStackTrace();
}
return str;
}
}
static class FastWriter {
private final BufferedWriter bw;
public FastWriter() {
this.bw = new BufferedWriter(new OutputStreamWriter(System.out));
}
public void print(Object object) throws IOException {
bw.append("" + object);
}
public void println(Object object) throws IOException {
print(object);
bw.append("\n");
}
public void close() throws IOException {
bw.close();
}
}
public static void main (String[] args) throws java.lang.Exception
{
FastReader in=new FastReader();
FastWriter out = new FastWriter();
int T=in.nextInt();
while(T--!=0){
int N=in.nextInt();
out.println(N);
int c=0;
for(int i=1;i<=N;i++){
out.println(N);
int initial=1+c;
for(int j=1;j<=N;j++){
int next=initial+1;
if(next==N+1)
next=1;
out.println(j+" "+initial+" "+next);
initial=next;
}
c++;
}
}
out.close();
}
}
SnackUp CodeChef Solution in PYPY 3
import collections
def solve():
n=int(input())
q=collections.deque()
for i in range(n):
q.append((i+1,(i+1)%n +1))
print(n)
for _ in range(n):
print(n)
for i, (x,y) in enumerate(q,start=1):
print(i,x,y)
q.append(q.popleft())
for _ in range(int(input())):
solve()SnackUp CodeChef Solution in PYTH
t = int(raw_input())
for i in range(t):
N = int(raw_input())
print N
for k in range(N):
print N
for j in range(N):
p = (j+k)%N
q = (p+1)%N
print j+1, p+1, q+1
# endfor j
# endfor k
# endfor i
SnackUp CodeChef Solution in C#
using System;
using System.Text;
public class Test
{
private interface IInputReader
{
string ReadInput();
}
private class ConsoleReader : IInputReader
{
public string ReadInput() => Console.ReadLine().Trim();
}
public static void Main()
{
checked
{
var reader = new ConsoleReader();
var testsCount = int.Parse(reader.ReadInput());
StringBuilder sb = new StringBuilder();
for (int test = 0; test < testsCount; test++)
{
var str = reader.ReadInput();
var n = int.Parse(str);
if (n % 2 == 0)
{
sb.AppendLine((n * n / 2).ToString());
for (int i = 0; i < n; i+=2)
{
for (int j = 0; j < n; j+=2)
{
for (int k = 0; k < 2; k++)
{
sb.AppendLine(2.ToString());
sb.AppendLine($"{j + 1} {i + 1} {i + 2}");
sb.AppendLine($"{j + 2} {i + 1} {i + 2}");
}
}
}
}
else
{
sb.AppendLine((1 + (n * n - n) / 2).ToString());
int[][] row = new int[n][];
for (int i = 0; i < n; i++)
{
row[i] = new[] {i, (i + 1) % n};
}
int[][][] pairs = new int[n][][];
for (int i = 0; i < n; i++)
{
pairs[i] = row;
}
sb.AppendLine(n.ToString());
for (int i = 0; i < n; i++)
{
sb.AppendLine($"{i + 1} {pairs[i][i][0] + 1} {pairs[i][i][1] + 1}");
}
for (int c = 0; c < n; c++)
{
int r0 = 0;
int r1 = 1;
while (r1 < n && r0 < n)
{
if (r1 == c)
{
r1++;
continue;
}
if (r0 == c)
{
r0++;
r1 = r0 + 1;
continue;
}
sb.AppendLine(2.ToString());
sb.AppendLine($"{r0 + 1} {pairs[r0][c][0] + 1} {pairs[r0][c][1] + 1}");
sb.AppendLine($"{r1 + 1} {pairs[r0][c][0] + 1} {pairs[r0][c][1] + 1}");
r0 = r1 + 1;
r1 = r0 + 1;
}
}
}
}
Console.WriteLine(sb.ToString());
}
}
}SnackUp CodeChef Solution in GO
package main
import (
"bufio"
"fmt"
"os"
)
var out = bufio.NewWriter(os.Stdout)
func main() {
defer out.Flush()
var t int
for fmt.Scan(&t); t > 0; t-- {
solve()
}
}
func solve() {
var n int
fmt.Scan(&n)
fmt.Fprintln(out, n)
for i := 0; i < n; i++ {
fmt.Fprintln(out, n)
for j := 0; j < n; j++ {
fmt.Fprintln(out, j+1, (j+i)%n+1, (j+i+1)%n+1)
}
}
}SnackUp CodeChef Solution Review:
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Conclusion:
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This Problem is intended for audiences of all experiences who are interested in learning about Programming Language in a business context; there are no prerequisites.
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