Physical Address

304 North Cardinal St.
Dorchester Center, MA 02124

SnackUp CodeChef Solution

Problem -SnackUp CodeChef Solution

This website is dedicated for CodeChef solution where we will publish right solution of all your favourite CodeChef problems along with detailed explanatory of different competitive programming concepts and languages.

SnackUp CodeChef Solution in C++14

#include <iostream>
#define ll long long int
using namespace std;

int main()
{ ll t; cin >> t;
  // seive();
  while (t--) {

    ll n; cin >> n;
    cout<<n<<endl;
    for (ll j = 0; j <n; j++)
    {
      
      cout<<n<<endl;
      for (ll i = 0; i < n; i++)
      {
        cout<<i+1<<" "<<((i+j)%n)+1<<" "<<((i+j+1)%n)+1<<endl;
      }
      
    }
      
  }
  return 0;}

SnackUp CodeChef Solution in PYTH 3

def soln(n):
    arr = [(i, i+1) for i in range(1, n)]
    arr.append((1, n))
    print(n)
    for i in range(n):
        print(n)
        for j in range(n):
            print(j+1, *arr[(i+j)%n])

for _ in range(int(input())):
    n = int(input())
    soln(n)

SnackUp CodeChef Solution in C

#include <stdio.h>

int main(void) {
	// your code goes here
	int i,t;
	scanf("%d",&t);
	while(t--){
	    int n;
	    scanf("%d",&n);
	    printf("%d\n",n);
	    for(i=1;i<=n;i++){
	        printf("%d\n",n);
	        for(int j=1;j<=n;j++){
	            int x=j+i-1 , y=j+i;
	            if(x>n && x%n!=0)
	            {
	                x=x%n;
	            }
	            else if(x%n==0){
	                x=n;
	            }
	            if(y>n && y%n!=0){
	                 y=y%n;
	            }
	            else if(y%n==0){
	                y=n;
	            }
	            printf("%d %d %d\n",j,x,y);
	            }
	        }
	    }
	return 0;
}

SnackUp CodeChef Solution in JAVA

/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{    static class FastReader{
        BufferedReader br;
        StringTokenizer st;
        public FastReader(){
            br=new BufferedReader(new InputStreamReader(System.in));
        }
        String next(){
            while(st==null || !st.hasMoreTokens()){
                try {
                    st=new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }
        int nextInt(){
            return Integer.parseInt(next());
        }
        long nextLong(){
            return Long.parseLong(next());
        }
        double nextDouble(){
            return Double.parseDouble(next());
        }
        String nextLine(){
            String str="";
            try {
                str=br.readLine().trim();
            } catch (Exception e) {
                e.printStackTrace();
            }
            return str;
        }
    }
    static class FastWriter {
		private final BufferedWriter bw;

		public FastWriter() {
			this.bw = new BufferedWriter(new OutputStreamWriter(System.out));
		}

		public void print(Object object) throws IOException {
			bw.append("" + object);
		}

		public void println(Object object) throws IOException {
			print(object);
			bw.append("\n");
		}

		public void close() throws IOException {
			bw.close();
		}
	}
	public static void main (String[] args) throws java.lang.Exception
	{
		FastReader in=new FastReader();
        FastWriter out = new FastWriter();
		int T=in.nextInt();
		while(T--!=0){
		    int N=in.nextInt();
		    out.println(N);
		    int c=0;
		    for(int i=1;i<=N;i++){
		        out.println(N);
		        int initial=1+c;
		        for(int j=1;j<=N;j++){
		            int next=initial+1;
		            if(next==N+1)
		               next=1;
		            out.println(j+" "+initial+" "+next);
		            initial=next;
		        }
		        c++;
		    }
		}
		out.close();
	}
}

SnackUp CodeChef Solution in PYPY 3

import collections 

def solve():
    n=int(input())
    q=collections.deque()
    for i in range(n):
        q.append((i+1,(i+1)%n +1))
    print(n)
    for _ in range(n):
        print(n)
        for i, (x,y) in enumerate(q,start=1):
            print(i,x,y)
        q.append(q.popleft())
for _ in range(int(input())):
    solve()

SnackUp CodeChef Solution in PYTH

t = int(raw_input())
for i in range(t):
	N = int(raw_input())
	print N
	for k in range(N):
		print N
		for j in range(N):
			p = (j+k)%N
			q = (p+1)%N
			print j+1, p+1, q+1
		# endfor j
	# endfor k
# endfor i

SnackUp CodeChef Solution in C#

using System;
using System.Text;

public class Test
{
            private interface IInputReader
        {
	        string ReadInput();
        }

        private class ConsoleReader : IInputReader
        {
	        public string ReadInput() => Console.ReadLine().Trim();
        }
    
	public static void Main()
	{
		 	        checked
	        {
		        var reader = new ConsoleReader();
		        var testsCount = int.Parse(reader.ReadInput());
				StringBuilder sb = new StringBuilder();
		        for (int test = 0; test < testsCount; test++)
		        {
			        var str = reader.ReadInput();
			        var n = int.Parse(str);

			        if (n % 2 == 0)
			        {
				        sb.AppendLine((n * n / 2).ToString());
				        for (int i = 0; i < n; i+=2)
				        {
					        for (int j = 0; j < n; j+=2)
					        {
						        for (int k = 0; k < 2; k++)
						        {
									sb.AppendLine(2.ToString());
									sb.AppendLine($"{j + 1} {i + 1} {i + 2}");
									sb.AppendLine($"{j + 2} {i + 1} {i + 2}");
								}
					        } 
				        }
			        }
			        else
			        {
				        sb.AppendLine((1 + (n * n - n) / 2).ToString());

						int[][] row = new int[n][];
						for (int i = 0; i < n; i++)
						{
							row[i] = new[] {i, (i + 1) % n};
						}
						int[][][] pairs = new int[n][][];
						for (int i = 0; i < n; i++)
						{
							pairs[i] = row;
						}

						sb.AppendLine(n.ToString());
						for (int i = 0; i < n; i++)
						{
							sb.AppendLine($"{i + 1} {pairs[i][i][0] + 1} {pairs[i][i][1] + 1}");
						}

						for (int c = 0; c < n; c++)
						{
							int r0 = 0;
							int r1 = 1;
							while (r1 < n && r0 < n)
							{
								if (r1 == c)
								{
									r1++;
									continue;
								}

								if (r0 == c)
								{
									r0++;
									r1 = r0 + 1;
									continue;
								}

								sb.AppendLine(2.ToString());
								sb.AppendLine($"{r0 + 1} {pairs[r0][c][0] + 1} {pairs[r0][c][1] + 1}");
								sb.AppendLine($"{r1 + 1} {pairs[r0][c][0] + 1} {pairs[r0][c][1] + 1}");

								r0 = r1 + 1;
								r1 = r0 + 1;
							}
						}

			        }
		        }
				Console.WriteLine(sb.ToString());
	        }
	}
}

SnackUp CodeChef Solution in GO

package main

import (
	"bufio"
	"fmt"
	"os"
)

var out = bufio.NewWriter(os.Stdout)

func main() {
	defer out.Flush()
	var t int
	for fmt.Scan(&t); t > 0; t-- {
		solve()
	}
}

func solve() {
	var n int
	fmt.Scan(&n)
	fmt.Fprintln(out, n)
	for i := 0; i < n; i++ {
		fmt.Fprintln(out, n)
		for j := 0; j < n; j++ {
			fmt.Fprintln(out, j+1, (j+i)%n+1, (j+i+1)%n+1)
		}
	}
}
SnackUp CodeChef Solution Review:

In our experience, we suggest you solve this SnackUp CodeChef Solution and gain some new skills from Professionals completely free and we assure you will be worth it.

If you are stuck anywhere between any coding problem, just visit Queslers to get the SnackUp CodeChef Solution.

Find on CodeChef

Conclusion:

I hope this SnackUp CodeChef Solution would be useful for you to learn something new from this problem. If it helped you then don’t forget to bookmark our site for more Coding Solutions.

This Problem is intended for audiences of all experiences who are interested in learning about Programming Language in a business context; there are no prerequisites.

Keep Learning!

More Coding Solutions >>

Cognitive Class Answer

CodeChef Solution

Microsoft Learn

Leave a Reply

Your email address will not be published. Required fields are marked *