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# Sort an Array LeetCode Solution

## Problem – Sort an Array

Given an array of integers `nums`, sort the array in ascending order.

Example 1:

``````Input: nums = [5,2,3,1]
Output: [1,2,3,5]``````

Example 2:

``````Input: nums = [5,1,1,2,0,0]
Output: [0,0,1,1,2,5]``````

Constraints:

• `1 <= nums.length <= 5 * 104`
• `-5 * 104 <= nums[i] <= 5 * 104`

### Sort an Array LeetCode Solution in C++

``````void outPlaceMerge(vector<int> &nums, int low, int mid, int high) {
if (low >= high) return;
int l = low, r = mid + 1, k = 0, size = high - low + 1;
vector<int> sorted(size, 0);
while (l <= mid and r <= high)
sorted[k++] = nums[l] < nums[r] ? nums[l++] : nums[r++];
while (l <= mid)
sorted[k++] = nums[l++];
while (r <= high)
sorted[k++] = nums[r++];
for (k = 0; k < size; k++)
nums[k + low] = sorted[k];
}

void mergeSort(vector<int> &nums, int low, int high) {
if (low >= high) return;
int mid = (high - low) / 2 + low;
mergeSort(nums, low, mid);
mergeSort(nums, mid + 1, high);
outPlaceMerge(nums, low, mid, high);
}
``````

### Sort an Array LeetCode Solution in Java

``````class Solution {
public List<Integer> sortArray(int[] nums) {
List<Integer> res = new ArrayList<>();
if (nums == null || nums.length == 0) return res;
quickSort(nums, 0, nums.length - 1);
for (int i : nums) res.add(i);
return res;
}
private void quickSort(int[] nums, int l, int r) {
if (l >= r) return;
int mid = partition(nums, l, r);
quickSort(nums, l, mid);
quickSort(nums, mid + 1, r);
}
private int partition(int[] nums, int l, int r) {
int pivot = nums[l];
while (l < r) {
while (l < r && nums[r] >= pivot) r--;
nums[l] = nums[r];
while (l < r && nums[l] <= pivot) l++;
nums[r] = nums[l];
}
nums[l] = pivot;
return l;
}
}``````

### Sort an Array LeetCode Solution in Python

``````def quicksort(self, nums):
if len(nums) <= 1:
return nums

pivot = random.choice(nums)
lt = [v for v in nums if v < pivot]
eq = [v for v in nums if v == pivot]
gt = [v for v in nums if v > pivot]

return self.quicksort(lt) + eq + self.quicksort(gt)
``````
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