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# Sort Array By Parity LeetCode Solution

## Problem – Sort Array By Parity LeetCode Solution

Given an integer array `nums`, move all the even integers at the beginning of the array followed by all the odd integers.

Return any array that satisfies this condition.

Example 1:

``````Input: nums = [3,1,2,4]
Output: [2,4,3,1]
Explanation: The outputs [4,2,3,1], [2,4,1,3], and [4,2,1,3] would also be accepted.``````

Example 2:

``````Input: nums = 
Output: 
``````

Constraints:

• `1 <= nums.length <= 5000`
• `0 <= nums[i] <= 5000`

### Sort Array By Parity LeetCode Solution in C++

``````    vector<int> sortArrayByParity(vector<int> &A) {
for (int i = 0, j = 0; j < A.size(); j++)
if (A[j] % 2 == 0) swap(A[i++], A[j]);
return A;
}
``````

### Sort Array By Parity LeetCode Solution in Java

``````    public int[] sortArrayByParity(int[] A) {
for (int i = 0, j = 0; j < A.length; j++)
if (A[j] % 2 == 0) {
int tmp = A[i];
A[i++] = A[j];
A[j] = tmp;;
}
return A;
}
``````

### Sort Array By Parity LeetCode Solution in Python

``````class Solution:
def sortArrayByParity(self, A):
beg, end = 0, len(A) - 1

while beg <= end:
if A[beg] % 2 == 0:
beg += 1
else:
A[beg], A[end] = A[end], A[beg]
end -= 1
return A
``````
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