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Given an integer array `nums`

sorted in **non-decreasing** order, return *an array of the squares of each number sorted in non-decreasing order*.

**Example 1**

```
Input: nums = [-4,-1,0,3,10]
Output: [0,1,9,16,100]
Explanation: After squaring, the array becomes [16,1,0,9,100].
After sorting, it becomes [0,1,9,16,100].
```

**Example 2:**

```
Input: nums = [-7,-3,2,3,11]
Output: [4,9,9,49,121]
```

**Constraints:**

`1 <= nums.length <= 10`

^{4}`-10`

^{4}<= nums[i] <= 10^{4}`nums`

is sorted in**non-decreasing**order.

```
class Solution {
public int[] sortedSquares(int[] A) {
int n = A.length;
int[] result = new int[n];
int i = 0, j = n - 1;
for (int p = n - 1; p >= 0; p--) {
if (Math.abs(A[i]) > Math.abs(A[j])) {
result[p] = A[i] * A[i];
i++;
} else {
result[p] = A[j] * A[j];
j--;
}
}
return result;
}
}
```

```
class Solution {
public:
vector<int> sortedSquares(vector<int>& A) {
vector<int> res(A.size());
int l = 0, r = A.size() - 1;
for (int k = A.size() - 1; k >= 0; k--) {
if (abs(A[r]) > abs(A[l])) res[k] = A[r] * A[r--];
else res[k] = A[l] * A[l++];
}
return res;
}
};
```

```
def sortedSquares(self, A):
answer = collections.deque()
l, r = 0, len(A) - 1
while l <= r:
left, right = abs(A[l]), abs(A[r])
if left > right:
answer.appendleft(left * left)
l += 1
else:
answer.appendleft(right * right)
r -= 1
return list(answer)
```

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