Squares of a Sorted Array LeetCode Solution

Problem – Squares of a Sorted Array LeetCode Solution

Given an integer array nums sorted in non-decreasing order, return an array of the squares of each number sorted in non-decreasing order.

Example 1

Input: nums = [-4,-1,0,3,10]
Output: [0,1,9,16,100]
Explanation: After squaring, the array becomes [16,1,0,9,100].
After sorting, it becomes [0,1,9,16,100].

Example 2:

Input: nums = [-7,-3,2,3,11]
Output: [4,9,9,49,121]

Constraints:

• 1 <= nums.length <= 104
• -104 <= nums[i] <= 104
• nums is sorted in non-decreasing order.

Squares of a Sorted Array LeetCode Solution in Java

class Solution {
    public int[] sortedSquares(int[] A) {
        int n = A.length;
        int[] result = new int[n];
        int i = 0, j = n - 1;
        for (int p = n - 1; p >= 0; p--) {
            if (Math.abs(A[i]) > Math.abs(A[j])) {
                result[p] = A[i] * A[i];
                i++;
            } else {
                result[p] = A[j] * A[j];
                j--;
            }
        }
        return result;
    }
}

Squares of a Sorted Array LeetCode Solution in C++

class Solution {
public:
    vector<int> sortedSquares(vector<int>& A) {
        vector<int> res(A.size());
        int l = 0, r = A.size() - 1;
        for (int k = A.size() - 1; k >= 0; k--) {
            if (abs(A[r]) > abs(A[l])) res[k] = A[r] * A[r--];
            else res[k] = A[l] * A[l++];
        }
        return res;
    }
};

Squares of a Sorted Array LeetCode Solution in Python

def sortedSquares(self, A):
    answer = collections.deque()
    l, r = 0, len(A) - 1
    while l <= r:
        left, right = abs(A[l]), abs(A[r])
        if left > right:
            answer.appendleft(left * left)
            l += 1
        else:
            answer.appendleft(right * right)
            r -= 1
    return list(answer)

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