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Given an integer, n, print the following values for each integer i from 1 to n:
The four values must be printed on a single line in the order specified above for each i from 1 to n. Each value should be space-padded to match the width of the binary value of n.
A single integer denoting n.
1 <= n <= 99
Print n lines where each line i (in the range 1 <= i <= n ) contains the respective decimal, octal, capitalized hexadecimal, and binary values of i. Each printed value must be formatted to the width of the binary value of n.
Sample Input
17
Sample Output
1 1 1 1
2 2 2 10
3 3 3 11
4 4 4 100
5 5 5 101
6 6 6 110
7 7 7 111
8 10 8 1000
9 11 9 1001
10 12 A 1010
11 13 B 1011
12 14 C 1100
13 15 D 1101
14 16 E 1110
15 17 F 1111
16 20 10 10000
17 21 11 10001
N = int(raw_input())
width = len(str(bin(N)))-2
for num in range(1,N+1):
for base in 'doXb':
print '{0:{width}{base}}'.format(num, base=base, width=width),
print
N = int(input())
l = len(bin(N)) - 2
for i in range(1, N + 1):
f = ""
for c in "doXb":
if f:
f += " "
f += "{:>" + str(l) + c + "}"
print(f.format(i, i, i, i))
n = int(raw_input())
width = len("{0:b}".format(n))
for i in xrange(1,n+1):
print "{0:{width}d} {0:{width}o} {0:{width}X} {0:{width}b}".format(i, width=width)
def print_formatted(number):
width=len(bin(number))-2
for num in range(1,number+1):
for base in ('d', 'o', 'X', 'b'):
print("{0:{width}{base}}".format(num, base=base, width=width), end=' ')
print()
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