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# Subscriptions CodeChef Solution

## Problem – Subscriptions CodeChef Solution

A new TV streaming service was recently started in Chefland called the Chef-TV.

A group of NN friends in Chefland want to buy Chef-TV subscriptions. We know that 66 people can share one Chef-TV subscription. Also, the cost of one Chef-TV subscription is XX rupees. Determine the minimum total cost that the group of NN friends will incur so that everyone in the group is able to use Chef-TV.

### Input Format

• The first line contains a single integer TT — the number of test cases. Then the test cases follow.
• The first and only line of each test case contains two integers NN and XX — the size of the group of friends and the cost of one subscription.

### Output Format

For each test case, output the minimum total cost that the group will incur so that everyone in the group is able to use Chef-TV.

• 1≤T≤1000
• 1≤N≤100
• 1≤X≤1000

### Sample 1:

``````Input: 3
1 100
12 250
16 135
Output: 100
500
405``````

### Explanation:

• Test case 1: There is only one person in the group. Therefore he will have to buy 11 subscription. Therefore the total cost incurred is 100100.
• Test case 2: There are 1212 people in the group. Therefore they will have to buy 22 subscriptions. Therefore the total cost incurred is 500500.
• Test case 3: There are 1616 people in the group. Therefore they will have to buy 33 subscriptions. Therefore the total cost incurred is 405405

## Subscriptions CodeChef Solution in Java

``````/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
while (t-- > 0) {
int n = Integer.parseInt(st.nextToken());
int x = Integer.parseInt(st.nextToken());

System.out.println((int)(Math.ceil(n / 6.0) * x));
}
}
}
``````

## Subscriptions CodeChef Solution in Pyth 3

``````# cook your dish here
import math as m
for i in range(int(input())):
a,b=map(int,input().split())
print(m.ceil(a/6)*b)``````

## Subscriptions CodeChef Solution in C++17

``````#include <iostream>
using namespace std;

int main() {
int t;
cin>>t;
while(t--){
int n, x;
cin>>n>>x;
cout<<((n/6) + (n%6?1:0))*x<<endl;
}
return 0;
}
``````
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