Sum of Digits CodeChef Solution

Problem – Sum of Digits CodeChef Solution

You’re given an integer N. Write a program to calculate the sum of all the digits of N.

Input

The first line contains an integer T, the total number of testcases. Then follow T lines, each line contains an integer N.

Output

For each test case, calculate the sum of digits of N, and display it in a new line.

Constraints

• 1 ≤ T ≤ 1000
• 1 ≤ N ≤ 1000000

Example

Input: 3 
12345
31203
2123
Output: 15
9
8

Sum of Digits CodeChef Solution in Pyth 3

T = int(input())
res = []
for i in range(T):
    inpLine = input()
    r = 0
    for j in inpLine:
        r += int(j)
    res.append(r)
    
print(*res, sep="\n")

Sum of Digits CodeChef Solution in C++17

#include<bits/stdc++.h>
#define pf printf
#define sf scanf
#define db double 
#define z long long int 
using namespace std ;
#define MAXN 100001
#define xx 12345678901
#define fast ios_base::sync_with_stdio(false); cin.tie(NULL);
z i,j;
int main() 
{

    fast;
    z t;
    cin>>t;
    while(t--)
    {
        z ans=0;
        string s;
        cin>>s;
        for(i=0;i<s.length();i++)
        {
            ans+=(s[i]-'0');
        }
        cout << ans <<endl;
    }
   return 0;
}

Sum of Digits CodeChef Solution in Java

import java.util.*;
class Main{
   public static int sum(int n){
        int sum=0;
        while(n!=0){
            int r=n%10;
            sum+=r;
            n=n/10;
        }
        return sum;
    }
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
       int t = sc.nextInt();
        for(int i=0;i<t;i++){
            int n = sc.nextInt();
            System.out.println(sum(n));
        }
    }
}

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