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# Tasty Decisions CodeChef Solution

## Problem – Tasty Decisions CodeChef Solution

Chef is buying sweet things to prepare for Halloween!

The shop sells both chocolate and candy.

• Each bar of chocolate has a tastiness of X.
• Each piece of candy has a tastiness of Y.

One packet of chocolate contains 2 bars, while one packet of candy contains 5 pieces.

Chef can only buy one packet of something sweet, and so has to make a decision: which one should he buy in order to maximize the total tastiness of his purchase?

Print `Chocolate` if the packet of chocolate is tastier, `Candy` if the packet of candy is tastier, and `Either` if they have the same tastiness.

#### Input Format

• The first line of input will contain a single integer T, denoting the number of test cases.
• Each test case consists of one line of input, containing two space-separated integers X and Y — the tastiness of one bar of chocolate and one piece of candy, respectively.

#### Output Format

For each test case, output on a new line the answer:

• `Chocolate` if the packet of chocolate is tastier.
• `Candy` if the packet of candy is tastier.
• `Either` if they have the same tastiness.

You may print each character of the output in either uppercase or lowercase, i.e, `Candy``CANDY``CaNdY` and `cANDy` will all be treated as equivalent.

• 1≤T≤100
• 1≤X,Y≤10

#### Sample 1:

``````Input:
4
5 1
5 2
5 3
3 10
Output:
Chocolate
Either
Candy
Candy``````

#### Explanation:

Test case 1: The packet of chocolate has a tastiness of  2×5=10, while the packet of candy has a tastiness of 5×1=5. The chocolate is tastier.

Test case 2: The packet of chocolate has a tastiness of 2×5=10, while the packet of candy has a tastiness of  5×2=10. They have the same tastiness.

Test case 3: The packet of chocolate has a tastiness of 2×5=10, while the packet of candy has a tastiness of 5×3=15. The candy is tastier.

Test case 4: The packet of chocolate has a tastiness of 2×3=6, while the packet of candy has a tastiness of 5×10=50. The candy is tastier.

### Tasty Decisions CodeChef Solution in Python3

``````for i in range(int(input())):
a, b = map(int, input().split())
if a*2 == b*5 :
print("either")
elif a*2  < b*5:
print("candy")
else:
print("chocolate")``````

### Tasty Decisions CodeChef Solution in C++17

``````#include <bits/stdc++.h>
using namespace std;

int main() {
int t;
cin>>t;
while(t--){
int x,y;
cin>>x>>y;
if((x*2)>(y*5)){
cout<<"chocolate\n";
}
else if((y*5)>(x*2)){
cout<<"candy\n";
}
else cout<<"either\n";
}
return 0;
}
``````

### Tasty Decisions CodeChef Solution in Java

``````/* package codechef; // don't place package name! */

import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);

int n = sc.nextInt();

while (n-- > 0) {
int chocolate = sc.nextInt();
int candy = sc.nextInt();
if (2*chocolate > 5*candy) {
System.out.println("Chocolate");
} else if (2*chocolate < 5*candy) {
System.out.println("Candy");
} else {
System.out.println("Either");
}
}
}
}``````
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