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# Text Alignment Hacker Rank Solution – Queslers

## Problem: Text Alignment Hacker Rank Solution

You are given a partial code that is used for generating the HackerRank Logo of variable thickness. Your task is to replace the blank (______) with rjust, ljust or center.

#### Input Format

A single line containing the thickness value for the logo.

#### Constraints

0 < thickness < 50

#### Output Format

Output the desired logo.

Sample Input

5

Sample Output

H
HHH
HHHHH
HHHHHHH
HHHHHHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHHHHHHHHHHHHHHHHHHHHHH
HHHHHHHHHHHHHHHHHHHHHHHHH
HHHHHHHHHHHHHHHHHHHHHHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHH               HHHHH
HHHHHHHHH
HHHHHHH
HHHHH
HHH
H

### Text Alignment Hacker Rank Solution in Python 2

#Replace all ______ with rjust, ljust or center.

thickness = int(raw_input()) #This must me an odd number
c = 'H'

#Top Cone
for i in range(thickness):
print (c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1)

#Top Pillars
for i in range(thickness+1):
print (c*thickness).center(thickness*2)+(c*thickness).center(thickness*6)

#Middle Belt
for i in range((thickness+1)/2):
print (c*thickness*5).center(thickness*6)

#Bottom Pillars
for i in range(thickness+1):
print (c*thickness).center(thickness*2)+(c*thickness).center(thickness*6)

#Bottom Cone
for i in range(thickness):
print ((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6)

### Text Alignment Hacker Rank Solution in Python 3

#Replace all ______ with rjust, ljust or center.

thickness = int(input()) #This must be an odd number
c = 'H'

#Top Cone
for i in range(thickness):
print((c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1))

#Top Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))

#Middle Belt
for i in range((thickness+1)//2):
print((c*thickness*5).center(thickness*6))

#Bottom Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))

#Bottom Cone
for i in range(thickness):
print(((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6))

### Text Alignment Hacker Rank Solution in pypy

thickness = int(raw_input()) #This must be an odd number
c = 'H'

#Top Cone
for i in range(thickness):
print((c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1))

#Top Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))

#Middle Belt
for i in range((thickness+1)//2):
print((c*thickness*5).center(thickness*6))

#Bottom Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))

#Bottom Cone
for i in range(thickness):
print(((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6))

### Text Alignment Hacker Rank Solution in pypy3

# Enter your code here. Read input from STDIN. Print output to STDOUT

thickness = int(input()) #This must be an odd number
c = 'H'

#Top Cone
for i in range(thickness):
print((c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1))

#Top Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))

#Middle Belt
for i in range((thickness+1)//2):
print((c*thickness*5).center(thickness*6))

#Bottom Pillars
for i in range(thickness+1):
print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))

#Bottom Cone
for i in range(thickness):
print(((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6))
##### Text Alignment Hacker Rank Solution Review:

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