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# Text Wrap Hacker Rank Solution – Queslers

## Problem: Text Wrap Hacker Rank Solution

You are given a string S and width w.

Your task is to wrap the string into a paragraph of width w.

#### Input Format

The first line contains a string, S.

The second line contains the width, w.

#### Constraints

• 0 < len(S) < 1000
• 0 < w < len(S)

#### Output Format

Print the text wrapped paragraph.

Sample Input 0

```ABCDEFGHIJKLIMNOQRSTUVWXYZ
4```

Sample Output 0

```ABCD
EFGH
IJKL
IMNO
QRST
UVWX
YZ```

### Text Wrap Hacker Rank Solution in Python 2

```S = raw_input()
w = int(input())
print '\n'.join(S[w*i:w*(i+1)] for i in xrange(len(S)/w+1))```

### Text Wrap Hacker Rank Solution in Python 3

```def wrap(string, max_width):
wrapper = textwrap.TextWrapper(width=max_width)
dedented_text = textwrap.dedent(text=string)
result = wrapper.fill(text=dedented_text)
return result```

## Text Wrap Hacker Rank Solution in pypy

```# Enter your code here. Read input from STDIN. Print output to STDOUT
import textwrap
print textwrap.fill(raw_input(),int(raw_input()))```

## Text Wrap Hacker Rank Solution in pypy3

```def wrap(string, max_width):
return
string=str(input())
max_width=int(input())
#print (string)
#print(max_width)
print(textwrap.fill(string,max_width))```
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