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Chef really likes to compete on Codechef, and he has gained an impressive rating of *X*, where *X*>0. There is also a parallel universe, where ratings on Codechef are negative instead. The only thing that remains unchanged in the parallel universe is Chef’s love for competing on Codechef. Chef’s rating on Codechef in the parallel universe is *Y*, where *Y*<0.

Due to some cosmic event, the parallel universe has been destroyed, resulting in Chef forgetting both *X* and *Y*. He only remembers the sum *S*=*X*+*Y*. He wonders what the **maximum** possible product of his ratings is, given that he knows the sum of his ratings.

- The first line of input will contain an integer
*T*— the number of test cases. The description of*T*test cases follows. - The first and only line of each test case contains an integer
*S*, the sum of Chef’s ratings.

- For each test case, output the
**maximum**possible product of Chef’s ratings, given that he knows the sum of his ratings.

- 1≤
*T*≤10^3 - 0≤
*S*≤10^9

**Subtask #1 (100 points):** Original constraints

```
Input:
2
0
1
Output:
-1
-2
```

**Test case 1**: We have *X*>0 and *X*+*Y*=0. This implies that *Y*=−*X*. The product of ratings is −*X*^2, and the maximum possible product is −1.

```
/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
// your code goes here
Scanner scan=new Scanner(System.in);
int t=scan.nextInt();
while (t-->0){
int a=scan.nextInt();
//int b=scan.nextInt();
System.out.println((a*-1)-1);
}
}
}
```

```
# cook your dish here
for i in range(int(input())):
s=int(input())
print(-(s+1))
```

```
#include <iostream>
using namespace std;
int main() {
// your code goes here
int t,s;
cin>>t;
while(t--)
{
cin>>s;
cout<<-(s+1)<<endl;
}
return 0;
}
```

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