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In a coding contest, there are prizes for the top rankers. The prize scheme is as follows:
Find the total prize money over all the contestants.
For each test case, output the total prize money over all the contestants.
Input: 4
1000 100
1000 1000
80 1
400 30
Output: 19000
100000
890
6700
Test Case 1: Top 10 participants receive rupees 1000 and next 90 participants receive rupees 100 each. So, total prize money = 10 \cdot 1000 + 90 \cdot 100 = 19000=10⋅1000+90⋅100=19000.
Test Case 2: Top 10 participants receive rupees 1000 and next 90 participants receive rupees 1000 each. So, total prize money = 10 \cdot 1000 + 90 \cdot 1000 = 100000=10⋅1000+90⋅1000=100000.
Test Case 3: Top 10 participants receive rupees 80 and next 90 participants receive rupee 1 each. So, total prize money = 10 \cdot 80 + 90 \cdot 1 = 890=10⋅80+90⋅1=890.
Test Case 4: Top 10 participants receive rupees 400 and next 90 participants receive rupees 30 each. So, total prize money = 10 \cdot 400 + 90 \cdot 30 = 6700=10⋅400+90⋅30=6700.
for _ in range(int(input())):
x, y = map(int,input().split())
print(10*x + 90*y)
#include <bits/stdc++.h>
using namespace std;
int main () {
int x,y,t;
cin>>t;
while (t--)
{
cin>>x>>y;
cout << x*10 + y*90 <<endl;
}
}
import java.util.*;
import java.lang.*;
import java.io.*;
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
for(int i=1; i<=n; i++){
int x = sc.nextInt();
int y = sc.nextInt();
System.out.println((x*10) + (y*90));
}
}
}
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