Traffic jam CodeChef Solution

Problem -Traffic jam CodeChef Solution

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Traffic jam CodeChef Solution in C++17

#include<iostream>
#include<string.h>
#include<stdio.h>
#include<algorithm>
using namespace std;
const int M=1e5+5;
inline void rd(int &a){
	a=0;char c;
	while(c=getchar(),!isdigit(c));
	do a=a*10+(c^48);
		while(c=getchar(),isdigit(c));
}
struct node{
	int pos,val;
	inline bool operator<(const node &tmp)const{
		return val<tmp.val||val==tmp.val&&pos<tmp.pos;
	}
}th[M];
int dp[M],A[M],B[M];
#define bug(x) cout<<#x<<"="<<x<<" "
#define debug(x) cout<<#x<<"="<<x<<endl
inline void gao(){
	int n;cin>>n;
	for(int i=1;i<=n;++i)rd(A[i]),B[i-1]=A[i];
	sort(B,B+n);
	int s=unique(B,B+n)-B;
	for(int i=1;i<=n;++i)
		dp[i]=lower_bound(B,B+s,A[i])-B+1,th[i]=(node){i,dp[i]};
	int allc=0;
	sort(th+1,th+n+1);
	th[0].val=-1;
	memset(A,0,sizeof(A));
	th[n+1]=(node){0,0};
	for(int i=1,pos=0,l=1;i<=n+1;++i){
		if(th[i].val!=th[i-1].val){
			pos=th[i-1].pos;
			for(int j=l;j<i;++j)
				if(!A[th[j].pos])A[pos=th[j].pos]=++allc;
			l=i;
		}
		if(th[i].pos>pos)A[th[i].pos]=++allc;
	}
	memset(dp,0,sizeof(dp));
	int res=0,ans=0;
	for(int i=1;i<=n;++i)
		dp[A[i]]=1,res+=!dp[A[i]-1];
	for(--res;res;res>>=1,++ans);
	cout<<ans<<endl;
}
int main(){
	int _;
	for(cin>>_;_--;)gao();
	return 0;
}

Traffic jam CodeChef Solution in C++14

#include<iostream>
#include<string.h>
#include<stdio.h>
#include<algorithm>
using namespace std;
const int M=1e5+5;
inline void rd(int &a){
	a=0;char c;
	while(c=getchar(),!isdigit(c));
	do a=a*10+(c^48);
		while(c=getchar(),isdigit(c));
}
struct node{
	int pos,val;
	inline bool operator<(const node &tmp)const{
		return val<tmp.val||val==tmp.val&&pos<tmp.pos;
	}
}th[M];
int dp[M],A[M],B[M];
#define bug(x) cout<<#x<<"="<<x<<" "
#define debug(x) cout<<#x<<"="<<x<<endl
inline void gao(){
	int n;cin>>n;
	for(int i=1;i<=n;++i)rd(A[i]),B[i-1]=A[i];
	sort(B,B+n);
	int s=unique(B,B+n)-B;
	for(int i=1;i<=n;++i)
		dp[i]=lower_bound(B,B+s,A[i])-B+1,th[i]=(node){i,dp[i]};
	int allc=0;
	sort(th+1,th+n+1);
	th[0].val=-1;
	memset(A,0,sizeof(A));
	th[n+1]=(node){0,0};
	for(int i=1,pos=0,l=1;i<=n+1;++i){
		if(th[i].val!=th[i-1].val){
			pos=th[i-1].pos;
			for(int j=l;j<i;++j)
				if(!A[th[j].pos])A[pos=th[j].pos]=++allc;
			l=i;
		}
		if(th[i].pos>pos)A[th[i].pos]=++allc;
	}
	memset(dp,0,sizeof(dp));
	int res=0,ans=0;
	for(int i=1;i<=n;++i)
		dp[A[i]]=1,res+=!dp[A[i]-1];
	for(--res;res;res>>=1,++ans);
	cout<<ans<<endl;
}
int main(){
	int _;
	for(cin>>_;_--;)gao();
	return 0;
}

Traffic jam CodeChef Solution in C

#include <stdio.h>
#include <stdlib.h>
#define siz 100000
#define S(a,b) if(a)return(b)
#define C(a) if(a)continue
 
typedef struct {
int x, n;
}st;
 
int o[siz];
st e[siz], *w[siz];
 
int A(const void *a, const void *b)
{
st *p=*(st**)a;
st *q=*(st**)b;
S(p->x<q->x,-1);
S(p->x>q->x,1);
S(p->n<q->n,-1);
S(p->n>q->n,1);
S(1,0);
}
 
main()
{
int fall, i, j, k, n, b, tmp;
for(scanf("%d",&fall); fall--; printf("%d\n",tmp))
	{
	for(i=!scanf("%d",&n); i<n; scanf("%d",&e[i].x),e[i].n=i,w[i]=e+i,o[i++]=0);
	qsort(w,n,sizeof(st*),A);
	for(i=!(b=1); i<n; i++)
		{
		C(o[i]);
		for(j=i+1; j<n&&o[j]; j++);
		C(j>=n);
		if(w[i]->n>w[j]->n)
			b++;
		else
			continue;
		for(k=j+1; k<n&&w[k]->x==w[j]->x&&w[k]->n<w[i]->n; k++);
		C(k>=n||w[k]->x!=w[j]->x);
		for(;k<n&&w[k]->x==w[j]->x; o[k++]=1);
		}
	for(tmp=0; b>1; b=(b+1)/2,tmp++);
	}
return 0;
}

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