Two Sum II – Input Array Is Sorted LeetCode Solution

Problem – Two Sum II – Input Array Is Sorted

Given a 1-indexed array of integers numbers that is already sorted in non-decreasing order, find two numbers such that they add up to a specific target number. Let these two numbers be numbers[index1] and numbers[index2] where 1 <= index1 < index2 <= numbers.length.

Return the indices of the two numbers, index1 and index2added by one as an integer array [index1, index2] of length 2.

The tests are generated such that there is exactly one solution. You may not use the same element twice.

Your solution must use only constant extra space.

Example 1:

Input: numbers = [2,7,11,15], target = 9
Output: [1,2]
Explanation: The sum of 2 and 7 is 9. Therefore, index1 = 1, index2 = 2. We return [1, 2].

Example 2:

Input: numbers = [2,3,4], target = 6
Output: [1,3]
Explanation: The sum of 2 and 4 is 6. Therefore index1 = 1, index2 = 3. We return [1, 3].

Example 3:

Input: numbers = [-1,0], target = -1
Output: [1,2]
Explanation: The sum of -1 and 0 is -1. Therefore index1 = 1, index2 = 2. We return [1, 2].

Constraints:

  • 2 <= numbers.length <= 3 * 104
  • -1000 <= numbers[i] <= 1000
  • numbers is sorted in non-decreasing order.
  • -1000 <= target <= 1000
  • The tests are generated such that there is exactly one solution.

Two Sum II – Input Array Is Sorted LeetCode Solution in Python

def twoSum1(self, numbers, target):
    l, r = 0, len(numbers)-1
    while l < r:
        s = numbers[l] + numbers[r]
        if s == target:
            return [l+1, r+1]
        elif s < target:
            l += 1
        else:
            r -= 1

Two Sum II – Input Array Is Sorted LeetCode Solution in Java

public int[] twoSum(int[] num, int target) {
    int[] indice = new int[2];
    if (num == null || num.length < 2) return indice;
    int left = 0, right = num.length - 1;
    while (left < right) {
        int v = num[left] + num[right];
        if (v == target) {
            indice[0] = left + 1;
            indice[1] = right + 1;
            break;
        } else if (v > target) {
            right --;
        } else {
            left ++;
        }
    }
    return indice;
}

Two Sum II – Input Array Is Sorted LeetCode Solution in C++

 vector<int> twoSum(vector<int>& numbers, int target) {
    
    int l = 0;
    int r = numbers.size() -1;
   
    while(l < r){
        if(numbers[l] + numbers[r] == target){
           
            return {l+1,r+1};;
        }
        else if(numbers[l] + numbers[r] > target){
            r--;
        }
        else{
            l++;
        }
    }
	return {};
}
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