Valid Mountain Array LeetCode Solution

Problem – Valid Mountain Array LeetCode Solution

Given an array of integers arr, return true if and only if it is a valid mountain array.

Recall that arr is a mountain array if and only if:

• arr.length >= 3
• There exists some i with 0 < i < arr.length - 1 such that:
  • arr[0] < arr[1] < ... < arr[i - 1] < arr[i]
  • arr[i] > arr[i + 1] > ... > arr[arr.length - 1]

Example 1:

Input: arr = [2,1]
Output: false

Example 2:

Input: arr = [3,5,5]
Output: false

Example 3:

Input: arr = [0,3,2,1]
Output: true

Constraints:

• 1 <= arr.length <= 104
• 0 <= arr[i] <= 104

Valid Mountain Array LeetCode Solution in C++

    bool validMountainArray(vector<int>& A) {
        int n = A.size(), i = 0, j = n - 1;
        while (i + 1 < n && A[i] < A[i + 1]) i++;
        while (j > 0 && A[j - 1] > A[j]) j--;
        return i > 0 && i == j && j < n - 1;
    }

Valid Mountain Array LeetCode Solution in Java

    public boolean validMountainArray(int[] A) {
        int n = A.length, i = 0, j = n - 1;
        while (i + 1 < n && A[i] < A[i + 1]) i++;
        while (j > 0 && A[j - 1] > A[j]) j--;
        return i > 0 && i == j && j < n - 1;
    }

Valid Mountain Array LeetCode Solution in Python

    def validMountainArray(self, A):
        i, j, n = 0, len(A) - 1, len(A)
        while i + 1 < n and A[i] < A[i + 1]: i += 1
        while j > 0 and A[j - 1] > A[j]: j -= 1
        return 0 < i == j < n - 1

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