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Validating Email Addresses With a Filter  Hacker Rank Solution – Queslers

Problem : Validating Email Addresses With a Filter Hacker Rank Solution

You are given an integer N followed by N email addresses. Your task is to print a list containing only valid email addresses in lexicographical order.
Valid email addresses must follow these rules:It must have the username@websitename.extension format type.
The username can only contain letters, digits, dashes and underscores.
The website name can only have letters and digits.
The maximum length of the extension is 3.
Concept :A filter takes a function returning True or False and applies it to a sequence, returning a list of only those members of the sequence where the function returned True. A Lambda function can be used with filters.
Let’s say you have to make a list of the squares of integers from 0 to 9(both included).

>> l = list(range(10))
>> l = list(map(lambda x:x*x, l))

Now, you only require those elements that are greater than 10 but less than 80.

>> l = list(filter(lambda x: x > 10 and x < 80, l))

Easy, isn’t it?


Input Format :

The first line of input is the integer N, the number of email addresses.
N lines follow, each containing a string.

Constraints :

Each line is a non-empty string.

Output Format :

Output a list containing the valid email addresses in lexicographical order. If the list is empty, just output an empty list, [].


Sample Input :

3
lara@hackerrank.com
brian-23@hackerrank.com
britts_54@hackerrank.com

Sample Output :

['brian-23@hackerrank.com', 'britts_54@hackerrank.com', 'lara@hackerrank.com']

Validating Email Addresses With a Filter Hacker Rank Solution in python 2

import re

n = int(raw_input())
ans = []
for i in range(n):
  s = raw_input()
  
  match = re.search(r'^[\w\d-]+\@[a-zA-Z0-9]+\.\w?\w?\w?$',s)
  if match:
    ans.append(s)
  
ans.sort()
print ans

Validating Email Addresses With a Filter Hacker Rank Solution in python 3

def fun(email):
    try:
        username, url = email.split("@")
        website, extension = url.split(".")
    except ValueError:
        return False
    
    if username.replace("-", "").replace("_", "").isalnum() is False:
        return False
    elif website.isalnum() is False:
        return False
    elif len(extension) > 3:
        return False
    else:
        return True

Validating Email Addresses With a Filter Hacker Rank Solution in pypy

import re

def fun(string):
	if string.count("@") == 1 and string.count('.') ==1:
		esplit = string.split('@')
		user =esplit[0]
		web = esplit[1].split('.')[0]
		ext = esplit[1].split('.')[1]
		return all([check_user(user),check_web(web),check_ext(ext)])
	else:
		return False


def check_user(strg, search=re.compile(r'[^a-zA-Z0-9-_]').search):
	lenght = True if len(strg)>0 else False
	return all([lenght,not(bool(search(strg)))])

def check_web(strg,search=re.compile(r'[^a-zA-Z0-9]').search):
	lenght = True if len(strg)>0 else False
	return all([lenght,not(bool(search(strg)))])

def check_ext(strg):
	lenght = False
	if len(strg) <= 3 and len(strg)>0:
		lenght = True
	return lenght

Validating Email Addresses With a Filter Hacker Rank Solution in pypy 3

import re
def fun(s):
    # return True if s is a valid email, else return False
    '''
    n=int(input())
    e=[]
    for _ in range[n]:
        e.append(input())
    user= e.split("@")[0]
    print(user)
    '''
    '''
    l = list(map(lambda x:x.split("@")[0], s))
    l = list(filter(lambda x: x > 10 and x < 80, l))
    '''
    #print(s)
    ptrn = re.compile("^[a-zA-Z][\w-]*@[a-zA-Z0-9]+\.[a-zA-Z]{1,3}$")
    result = ptrn.match(s)
    #l = list(filter(lambda x:x.match(ptrn) , s))
    return result
Validating Email Addresses With a Filter Hacker Rank Solution Review:

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