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Vedant has a hidden array of NN elements. Given the bitwise AND of all elements of the array, determine whether the total sum of the elements is odd, even or cannot be determined.
For each test case, output Even
if the sum of all elements in the hidden array is even, Odd
if the sum of all elements in the hidden array is odd, or Impossible
if the parity cannot be determined.
Note: You may print each character of the string in uppercase or lowercase (for example, the strings eVen
, EvEn
, even
and EVEN
will all be treated as identical).
3
1 11
1 2
74120341 829182732
Odd
Even
Impossible
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