Weird Palindrome Making CodeChef Solution

Problem -Weird Palindrome Making CodeChef Solution

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Weird Palindrome Making CodeChef Solution in C++17

#include <iostream>
using namespace std;

int main() {
	// your code goes here
	long long t;
	cin>>t;
	while(t--){
	    long long n;
	    cin>>n;
	    long long c=0;
	    long long a[n];
	    for(int i=0; i<n; i++){
	        cin>>a[i];
	        if(a[i]%2!=0){
	            c++;
	        }
	    }
	    if(c<=1){
	        cout<<0<<endl;
	    }
	    else if(c==2){
	        cout<<1<<endl;
	    }
	    else{
	        cout<<c/2<<endl;
	    }
	    
	}
	return 0;
}

Weird Palindrome Making CodeChef Solution in C++14

//Weird Palidrome Making

#include <iostream>
#define ll long long
using namespace std;

void Solve(){
    int N;
    cin >> N;
    
    int cnt = 0;
    
    ll x;
    for( int i = 0; i < N; i++){
        cin >> x;
        if((x & 1) == 1) cnt++;
    }
    cout << cnt / 2 << "\n";
    
    
}

int main() {
	// your code goes here
	ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    
	int T;
	cin >> T;
	while(T --){
	    Solve();
	}
	return 0;
}

Weird Palindrome Making CodeChef Solution in PYTH 3

# cook your dish here
for _ in range(int(input())):
    n = int(input())
    ch = [int(x) for x in input().split()]
    o = 0
    for c in ch:
        if c%2==1:  o+=1
    print(int(o/2))
        

Weird Palindrome Making CodeChef Solution in C

#include <stdio.h>
#define ml long long int 
int main() 
{
    ml t;
    scanf("%lld",&t);
    while(t--)
    {
        ml num,value,mvar=0;
        
        scanf("%lld",&num);
        for(ml i=0;i<num;i++)
        {
            scanf("%lld",&value);
            if(value%2==1) mvar+=1;
        }
        if(mvar%2==1) mvar-=1;
        printf("%lld\n",mvar/2);
        
    }
    return 0;
}

Weird Palindrome Making CodeChef Solution in JAVA

import java.util.Scanner;
class WeirdPalindromeMaking
{
        public static void main(String[] args)
        {
            int checking;
            Scanner sc=new Scanner(System.in);
            checking=sc.nextInt();
            while(checking-->0)
            {
                int n,i,kcpd;
                n=sc.nextInt();
                int manam_manam_amalapuram[];
                manam_manam_amalapuram=new int[n];
                kcpd=0;
                for(i=0;i<n;i++)
                {
                     manam_manam_amalapuram[i]=sc.nextInt();
                     if(((manam_manam_amalapuram[i]>>1)<<1)!=manam_manam_amalapuram[i])
                     kcpd++;
                }
                if(((kcpd<<1)>>1)!=kcpd)
                kcpd--;
                System.out.println(kcpd>>1);
            }
            sc.close();
        }
}

Weird Palindrome Making CodeChef Solution in PYPY 3

for t in range(int(input())):
    n=int(input())
    a=input().split()
    odd=0
    for i in range(n):
        a[i]=int(a[i])
        if a[i]%2!=0:
            odd=odd+1
    print(odd//2)

Weird Palindrome Making CodeChef Solution in PYTH

t = int(raw_input())
for i in range(t):
	N = int(raw_input())
	st = raw_input().split()
	n = 0
	for x in st:
		n += int(x)%2
	# endfor x
	r = n/2
	print r
# endfor i

Weird Palindrome Making CodeChef Solution in C#

using System;
using System.Linq;
public class Test
{
	public static void Main()
	{
		// your code goes here
		  string line = Console.ReadLine();
	    int t= Convert.ToInt32(line);
	    
	    while(t>0)
	    {
            line = Console.ReadLine();
            line = Console.ReadLine();
            int[] a= line.Split(' ').Select(x=> Convert.ToInt32(x)).ToArray();
            int count =0;
            for(int i=0;i<a.Length;i++)
            {
                if(!(a[i]%2==0))
                  count++;
            }
            
            Console.WriteLine(count==0?0:count/2);
            
            t--;
            
	    }
	}
}

Weird Palindrome Making CodeChef Solution in NODEJS

process.stdin.resume();
process.stdin.setEncoding('utf-8');

let inputString = '';
let currentLine = 0;

process.stdin.on('data', inputStdin => {
    inputString += inputStdin;
});

process.stdin.on('end', _ => {
    inputString = inputString.trim().split('\n').map(string => {
        return string.trim();
    });
    
    main();    
});

function readLine() {
    return inputString[currentLine++];
}

const getMaxLessThanK = (A) => {
    let c = 0;
    for(let i = 0 ; i < A.length; i++) {
        if(A[i] % 2 === 1) c++;
    }
    return c % 2 === 1 ? (c - 1) / 2 : c / 2;
}

function main() {
    const q = +(readLine());

    for (let i = 0; i < q; i++) {
        const N = +(readLine());
        const arr = readLine().split(' ').map(Number);
        console.log(getMaxLessThanK(arr));
    }
}

Weird Palindrome Making CodeChef Solution in GO

package main

import (
	"bufio"
	"bytes"
	"fmt"
	"os"
)

func main() {
	reader := bufio.NewReader(os.Stdin)
	var buf bytes.Buffer
	tc := readNum(reader)

	for tc > 0 {
		tc--
		n := readNum(reader)
		A := readNNums(reader, n)
		res := solve(A)
		buf.WriteString(fmt.Sprintf("%d\n", res))
	}

	fmt.Printf(buf.String())
}

func readInt(bytes []byte, from int, val *int) int {
	i := from
	sign := 1
	if bytes[i] == '-' {
		sign = -1
		i++
	}
	tmp := 0
	for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
		tmp = tmp*10 + int(bytes[i]-'0')
		i++
	}
	*val = tmp * sign
	return i
}

func readNum(reader *bufio.Reader) (a int) {
	bs, _ := reader.ReadBytes('\n')
	readInt(bs, 0, &a)
	return
}

func readTwoNums(reader *bufio.Reader) (a int, b int) {
	res := readNNums(reader, 2)
	a, b = res[0], res[1]
	return
}

func readThreeNums(reader *bufio.Reader) (a int, b int, c int) {
	res := readNNums(reader, 3)
	a, b, c = res[0], res[1], res[2]
	return
}

func readNNums(reader *bufio.Reader, n int) []int {
	res := make([]int, n)
	x := 0
	bs, _ := reader.ReadBytes('\n')
	for i := 0; i < n; i++ {
		for x < len(bs) && (bs[x] < '0' || bs[x] > '9') && bs[x] != '-' {
			x++
		}
		x = readInt(bs, x, &res[i])
	}
	return res
}

func readUint64(bytes []byte, from int, val *uint64) int {
	i := from

	var tmp uint64
	for i < len(bytes) && bytes[i] >= '0' && bytes[i] <= '9' {
		tmp = tmp*10 + uint64(bytes[i]-'0')
		i++
	}
	*val = tmp

	return i
}

func solve(A []int) int {
	// only need to change odd numbers to some odd number, and leave the max odd
	var cnt int
	for _, a := range A {
		if a%2 == 1 {
			cnt++
		}
	}
	return cnt / 2
}

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