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Wiggle Sort II LeetCode Solution – Queslers

Problem – Wiggle Sort II

Given an integer array `nums`, reorder it such that `nums[0] < nums[1] > nums[2] < nums[3]...`.

You may assume the input array always has a valid answer.

Example 1:

``````Input: nums = [1,5,1,1,6,4]
Output: [1,6,1,5,1,4]
Explanation: [1,4,1,5,1,6] is also accepted.
``````

Example 2:

``````Input: nums = [1,3,2,2,3,1]
Output: [2,3,1,3,1,2]``````

Constraints:

• `1 <= nums.length <= 5 * 104`
• `0 <= nums[i] <= 5000`
• It is guaranteed that there will be an answer for the given input `nums`.

Follow Up: Can you do it in `O(n)` time and/or in-place with `O(1)` extra space?

Wiggle Sort II LeetCode Solution in Java

``````   public void wiggleSort(int[] nums) {
int median = findKthLargest(nums, (nums.length + 1) / 2);
int n = nums.length;

int left = 0, i = 0, right = n - 1;

while (i <= right) {

if (nums[newIndex(i,n)] > median) {
swap(nums, newIndex(left++,n), newIndex(i++,n));
}
else if (nums[newIndex(i,n)] < median) {
swap(nums, newIndex(right--,n), newIndex(i,n));
}
else {
i++;
}
}

}

private int newIndex(int index, int n) {
return (1 + 2*index) % (n | 1);
}
``````

Wiggle Sort II LeetCode Solution in Python

``````def wiggleSort(self, nums):
nums.sort()
half = len(nums[::2])
nums[::2], nums[1::2] = nums[:half][::-1], nums[half:][::-1]``````

Wiggle Sort II LeetCode Solution in C++

``````void wiggleSort(vector<int>& nums) {
vector<int> sorted(nums);
sort(sorted.begin(), sorted.end());
for (int i=nums.size()-1, j=0, k=i/2+1; i>=0; i--)
nums[i] = sorted[i&1 ? k++ : j++];
}
``````
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