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# Write a function Hacker Rank Solution – Queslers

## Problem: Write a function Hacker Rank Solution

We add a Leap Day on February 29, almost every four years. The leap day is an extra, or intercalary, day and we add it to the shortest month of the year, February.
In the Gregorian calendar three criteria must be taken into account to identify leap years:

• The year can be evenly divided by 4;
• If the year can be evenly divided by 100, it is NOT a leap year, unless;
• The year is also evenly divisible by 400. Then it is a leap year.

This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years.SourceTask
You are given the year, and you have to write a function to check if the year is leap or not.Note that you have to complete the function and remaining code is given as template.Input FormatRead y, the year that needs to be checked.ConstraintsOutput FormatOutput is taken care of by the template. Your function must return a boolean value (True/False)Sample Input

``````1990
``````

Sample Output

``````False
``````

Explanation1990 is not a multiple of 4 hence it’s not a leap year.

### Write a function Hacker Rank Solution

``````def is_leap(year):
leap = False

if year%4==0:
if year%100==0:
if year%400==0:
leap=True
else:
leap=False
else:
leap=True
else:
leap=False

return leap

year = int(input())
print(is_leap(year))``````
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