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# XML 2 – Find the Maximum Depth Hacker Rank Solution – Queslers

## Problem : XML 2 – Find the Maximum Depth Hacker Rank Solution

You are given a valid XML document, and you have to print the maximum level of nesting in it. Take the depth of the root as 0.

#### Input Format :

The first line contains N, the number of lines in the XML document.
The next N lines follow containing the XML document.

#### Output Format :

Output a single line, the integer value of the maximum level of nesting in the XML document.

#### Sample Input :

``````6
<feed xml:lang='en'>
<title>HackerRank</title>
<subtitle lang='en'>Programming challenges</subtitle>
<updated>2013-12-25T12:00:00</updated>
</feed>
``````

#### Sample Output :

``````1
``````

#### Explanation :

Here, the root is a feed tag, which has depth of 0.
The tags title, subtitle, link and updated all have a depth of 1.
Thus, the maximum depth is 1.

### XML 2 – Find the Maximum Depth Hacker Rank Solution in python 2

``````# Enter your code here. Read input from STDIN. Print output to STDOUT
def depth(tree):
dp = 0
if tree is not None:
for i in tree:
dp = max(dp,  depth(i) + 1)
return dp
n = int(raw_input())
xml = ""
for i in range(n):
xml += raw_input()
import xml.etree.ElementTree as etree
tree = etree.fromstring(xml)

print depth(tree)``````

### XML 2 – Find the Maximum Depth Hacker Rank Solution in python 3

``````global maxdepth
maxdepth = -1
def depth(elem, level):
global maxdepth
if (level == maxdepth):
maxdepth += 1

for child in elem:
depth(child, level + 1)``````

### XML 2 – Find the Maximum Depth Hacker Rank Solution in pypy

``````maxdepth = 0
def depth(elem, level):
global maxdepth

if (level == maxdepth):
maxdepth += 1

for child in elem:
depth(child, level + 1)``````

### XML 2 – Find the Maximum Depth Hacker Rank Solution in pypy 3

``````maxdepth = 0
def depth(elem, level):
global maxdepth

for child in elem:
depth(child, level+1)
maxdepth = max(maxdepth, level+2)``````
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