Yet Another Cute Girl CodeChef Solution

Problem -Yet Another Cute Girl CodeChef Solution

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This website is dedicated for CodeChef solution where we will publish right solution of all your favourite CodeChef problems along with detailed explanatory of different competitive programming concepts and languages.

Yet Another Cute Girl CodeChef Solution in C++17

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#include <bits/stdc++.h>
using namespace std;


bool isPrime[10000];
void init()
{
	// Since range is very small so not used Sieve
	for (int i = 2; i < sizeof(isPrime); ++i) {
		int j = 2;
		for (; j * j <= i; ++j) {
			if (i % j == 0) {
				break;
			}
		}
		if (j * j > i) isPrime[i] = true;
	}
}
main()
{
	init();
	int testCases, divisors[1000005];
	scanf("%d", &testCases);
	while(testCases--) {
		long long L, R;
		scanf("%lld%lld", &L, &R);
		for(long long i=L; i<=R; i++) divisors[i-L] = 0;

		for(long long i=1; i*i <= R; i++) {
			long long square = i*i;

			for(long long j=( (L-1) / i + 1) * i; j <= R; j += i) {
				if (j < square) continue; 

				if( square == j ) 
					divisors[j-L] += 1;
				else divisors[j-L] += 2; 
			}
		}
		int ans = 0;
		for(long long i = L; i <= R; i++) if(isPrime[divisors[i-L]]) ans++;
		printf("%d\n",ans);
	}
}

Yet Another Cute Girl CodeChef Solution in C++14

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#include <bits/stdc++.h>

#pragma optimization_level 3
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("Ofast")//Comment optimisations for interactive problems (use endl)
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")

using namespace std;

struct PairHash {inline std::size_t operator()(const std::pair<int, int> &v) const { return v.first * 31 + v.second; }};

// speed
#define Code ios_base::sync_with_stdio(false);
#define By ios::sync_with_stdio(0);
#define Sumfi cout.tie(NULL);

// alias
using ll = long long;
using ld = long double;
using ull = unsigned long long;

// constants
const ld PI = 3.14159265358979323846;  /* pi */
const ll INF = 1e18;
const ld EPS = 1e-9;
const ll MAX_N = 101010;
const ll mod = 998244353;

// typedef
typedef pair<ll, ll> pll;
typedef vector<pll> vpll;
typedef array<ll,3> all3;
typedef array<ll,5> all5;
typedef vector<all3> vall3;
typedef vector<all5> vall5;
typedef vector<ld> vld;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef deque<ll> dqll;
typedef deque<pll> dqpll;
typedef pair<string, string> pss;
typedef vector<pss> vpss;
typedef vector<string> vs;
typedef vector<vs> vvs;
typedef unordered_set<ll> usll;
typedef unordered_set<pll, PairHash> uspll;
typedef unordered_map<ll, ll> umll;
typedef unordered_map<pll, ll, PairHash> umpll;

// macros
#define rep(i,m,n) for(ll i=m;i<n;i++)
#define rrep(i,m,n) for(ll i=n;i>=m;i--)
#define all(a) begin(a), end(a)
#define rall(a) rbegin(a), rend(a)
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
#define INF(a) memset(a,0x3f3f3f3f3f3f3f3fLL,sizeof(a))
#define ASCEND(a) iota(all(a),0)
#define sz(x) ll((x).size())
#define BIT(a,i) (a & (1ll<<i))
#define BITSHIFT(a,i,n) (((a<<i) & ((1ll<<n) - 1)) | (a>>(n-i)))
#define pyes cout<<"Yes\n";
#define pno cout<<"No\n";
#define endl "\n"
#define pneg1 cout<<"-1\n";
#define ppossible cout<<"Possible\n";
#define pimpossible cout<<"Impossible\n";
#define TC(x) cout<<"Case #"<<x<<": ";
#define X first
#define Y second

// utility functions
template <typename T>
void print(T &&t)  { cout << t << "\n"; }
template<typename T>
void printv(vector<T>v){ll n=v.size();rep(i,0,n){cout<<v[i];if(i+1!=n)cout<<' ';}cout<<endl;}
template<typename T>
void printvln(vector<T>v){ll n=v.size();rep(i,0,n)cout<<v[i]<<endl;}
void fileIO(string in = "input.txt", string out = "output.txt") {freopen(in.c_str(),"r",stdin); freopen(out.c_str(),"w",stdout);}
void readf() {freopen("", "rt", stdin);}
template<typename T>
void readv(vector<T>& v){rep(i,0,sz(v)) cin>>v[i];}
template<typename T, typename U>
void readp(pair<T,U>& A) {cin>>A.first>>A.second;}
template<typename T, typename U>
void readvp(vector<pair<T,U>>& A) {rep(i,0,sz(A)) readp(A[i]); }
void readvall3(vall3& A) {rep(i,0,sz(A)) cin>>A[i][0]>>A[i][1]>>A[i][2];}
void readvall5(vall5& A) {rep(i,0,sz(A)) cin>>A[i][0]>>A[i][1]>>A[i][2]>>A[i][3]>>A[i][4];}
void readvvll(vvll& A) {rep(i,0,sz(A)) readv(A[i]);}

struct Combination {
    vll fac, inv;
    ll n, MOD;

    ll modpow(ll n, ll x, ll MOD = mod) { if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }

    Combination(ll _n, ll MOD = mod): n(_n + 1), MOD(MOD) {
        inv = fac = vll(n,1);
        rep(i,1,n) fac[i] = fac[i-1] * i % MOD;
        inv[n - 1] = modpow(fac[n - 1], MOD - 2, MOD);
        rrep(i,1,n - 2) inv[i] = inv[i + 1] * (i + 1) % MOD;
    }

    ll fact(ll n) {return fac[n];}
    ll nCr(ll n, ll r) {
        if(n < r or n < 0 or r < 0) return 0;
        return fac[n] * inv[r] % MOD * inv[n-r] % MOD;
    }
};

struct Matrix {
    ll r,c;
    vvll matrix;
    Matrix(ll r, ll c, ll v = 0): r(r), c(c), matrix(vvll(r,vll(c,v))) {}

    Matrix operator*(const Matrix& B) const {
        Matrix res(r, B.c);
        rep(i,0,r) rep(j,0,B.c) rep(k,0,B.r) {
                    res.matrix[i][j] = (res.matrix[i][j] + matrix[i][k] * B.matrix[k][j] % mod) % mod;
                }
        return res;
    }

    Matrix copy() {
        Matrix copy(r,c);
        copy.matrix = matrix;
        return copy;
    }

    Matrix pow(ll n) {
        assert(r == c);
        Matrix res(r,r);
        Matrix now = copy();
        rep(i,0,r) res.matrix[i][i] = 1;
        while(n) {
            if(n & 1) res = res * now;
            now = now * now;
            n /= 2;
        }
        return res;
    }
};

// geometry data structures
template <typename T>
struct Point {
    T y,x;
    Point(T y, T x) : y(y), x(x) {}
    Point(pair<T,T> p) : y(p.first), x(p.second) {}
    Point() {}
    void input() {cin>>y>>x;}
    friend ostream& operator<<(ostream& os, const Point<T>& p) { os<<p.y<<' '<<p.x<<'\n'; return os;}
    Point<T> operator+(Point<T>& p) {return Point<T>(y + p.y, x + p.x);}
    Point<T> operator-(Point<T>& p) {return Point<T>(y - p.y, x - p.x);}
    Point<T> operator*(ll n) {return Point<T>(y*n,x*n); }
    Point<T> operator/(ll n) {return Point<T>(y/n,x/n); }
    bool operator<(const Point &other) const {if (x == other.x) return y < other.y;return x < other.x;}
    Point<T> rotate(Point<T> center, ld angle) {
        ld si = sin(angle * PI / 180.), co = cos(angle * PI / 180.);
        ld y = this->y - center.y;
        ld x = this->x - center.x;

        return Point<T>(y * co - x * si + center.y, y * si + x * co + center.x);
    }
    ld distance(Point<T> other) {
        T dy = abs(this->y - other.y);
        T dx = abs(this->x - other.x);
        return sqrt(dy * dy + dx * dx);
    }

    T norm() { return x * x + y * y; }
};

template<typename T>
struct Line {
    Point<T> A, B;
    Line(Point<T> A, Point<T> B) : A(A), B(B) {}
    Line() {}

    void input() {
        A = Point<T>();
        B = Point<T>();
        A.input();
        B.input();
    }

    T ccw(Point<T> &a, Point<T> &b, Point<T> &c) {
        T res = a.x * b.y + b.x * c.y + c.x * a.y;
        res -= (a.x * c.y + b.x * a.y + c.x * b.y);
        return res;
    }

    bool isIntersect(Line<T> o) {
        T p1p2 = ccw(A,B,o.A) * ccw(A,B,o.B);
        T p3p4 = ccw(o.A,o.B,A) * ccw(o.A,o.B,B);
        if (p1p2 == 0 && p3p4 == 0) {
            pair<T,T> p1(A.y, A.x), p2(B.y,B.x), p3(o.A.y, o.A.x), p4(o.B.y, o.B.x);
            if (p1 > p2) swap(p2, p1);
            if (p3 > p4) swap(p3, p4);
            return p3 <= p2 && p1 <= p4;
        }
        return p1p2 <= 0 && p3p4 <= 0;
    }

    pair<bool,Point<ld>> intersection(Line<T> o) {
        if(!this->intersection(o)) return {false, {}};
        ld det = 1. * (o.B.y-o.A.y)*(B.x-A.x) - 1.*(o.B.x-o.A.x)*(B.y-A.y);
        ld t = ((o.B.x-o.A.x)*(A.y-o.A.y) - (o.B.y-o.A.y)*(A.x-o.A.x)) / det;
        return {true, {A.y + 1. * t * (B.y - A.y), B.x + 1. * t * (B.x - A.x)}};
    }

    //@formula for : y = ax + b
    //@return {a,b};
    pair<ld, ld> formula() {
        T y1 = A.y, y2 = B.y;
        T x1 = A.x, x2 = B.x;
        if(y1 == y2) return {1e9, 0};
        if(x1 == x2) return {0, 1e9};
        ld a = 1. * (y2 - y1) / (x2 - x1);
        ld b = -x1 * a + y1;
        return {a, b};
    }
};

template<typename T>
struct Circle {
    Point<T> center;
    T radius;
    Circle(T y, T x, T radius) : center(Point<T>(y,x)), radius(radius) {}
    Circle(Point<T> center, T radius) : center(center), radius(radius) {}
    Circle() {}

    void input() {
        center = Point<T>();
        center.input();
        cin>>radius;
    }

    bool circumference(Point<T> p) {
        return (center.x - p.x) * (center.x - p.x) + (center.y - p.y) * (center.y - p.y) == radius * radius;
    }

    bool intersect(Circle<T> c) {
        T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
        return (radius - c.radius) * (radius - c.radius) <= d and d <= (radius + c.radius) * (radius + c.radius);
    }

    bool include(Circle<T> c) {
        T d = (center.x - c.center.x) * (center.x - c.center.x) + (center.y - c.center.y) * (center.y - c.center.y);
        return d <= radius * radius;
    }
};

ll __gcd(ll x, ll y) { return !y ? x : __gcd(y, x % y); }
all3 __exgcd(ll x, ll y) { if(!y) return {x,1,0}; auto [g,x1,y1] = __exgcd(y, x % y); return {g, y1, x1 - (x/y) * y1}; }
ll __lcm(ll x, ll y) { return x / __gcd(x,y) * y; }
ll modpow(ll n, ll x, ll MOD = mod) { n%=MOD; if(!x) return 1; ll res = modpow(n,x>>1,MOD); res = (res * res) % MOD; if(x&1) res = (res * n) % MOD; return res; }

ll prime[MAX_N];
void init() {
    prime[0] = prime[1] = true;
    rep(i,2,MAX_N) {
        if(prime[i]) continue;
        for(ll j = i * i; j < MAX_N; j += i) prime[j] = true;
    }
}

ll solve(ll l, ll r) {
    vll A(r-l + 1);
    for(ll i = 1; i * i <= r; i++) {
        ll pow2 = i * i;
        for(ll j = ((l - 1) / i + 1) * i; j <= r; j += i) {
            if(j < pow2) continue;
            if(pow2 == j) A[j-l] += 1;
            else A[j-l] += 2;
        }
    }
    ll res = 0;
    rep(i,0,sz(A)) if(!prime[A[i]]) res += 1;
    return res;
}
int main() {
    Code By Sumfi
    cout.precision(12);
    init();
    ll tc = 1;
    cin>>tc;
    rep(i,1,tc+1) {
        ll l,r;
        cin>>l>>r;
        print(solve(l,r));
    }
    return 0;
}

Yet Another Cute Girl CodeChef Solution in PYTH 3

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from bisect import bisect
from math import sqrt,floor
prime = []
isprime = [True]*(10**6 + 2)
isprime[0] = False
isprime[1] = False
for x in range(2,10**6+2):
    if(isprime[x]):
        prime.append(x)
        for i in range(2*x,10**6+2,x):
            isprime[i] = False
for _ in range(int(input())):
    a,b = map(int,input().split())
    sq_rt = floor(sqrt(b)) + 1
    index = bisect(prime,sq_rt)
    arr = prime[:index]
    ans = 0
    if(a<=1):
        a=2
    isprime = [True]*(b-a+1)
    for x in arr:
        st = floor(a/x)*x
        if(st<a):
            st+=x
        if(st==x):
            st+=x
        st = st-a
        for y in range(st,b-a+1,x):
            if(isprime[y]==True):
                isprime[y] = [x]
            else:
                isprime[y].append(x)
    for x in range(b-a+1):
        if(isprime[x]==True):
            ans+=1
        else:
            temp = 1
            val = a+x
            if(sqrt(val) == int(sqrt(val))):
                c = 0
                while(val>1 and c<len(isprime[x])):
                    elem = isprime[x][c]
                    t = 0
                    while(val%elem==0):
                        t+=1
                        val = val//elem
                    temp *= (1+t)
                    c+=1
                pos = bisect(prime,temp) - 1
                if(prime[pos]==temp):
                    ans+=1
            else:
                continue
    print(ans)

Yet Another Cute Girl CodeChef Solution in C

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#include <stdio.h>


void scani(int *z){
    *z=0;
    char c;
    int mul=1;
    c=getchar_unlocked();
    while(c!='-'&&( c<'0'||c>'9'))
        c=getchar_unlocked();
    if(c=='-')
        mul=-1,c=getchar_unlocked();
    while(c>='0'&&c<='9'){
        *z=(*z<<3)+(*z<<1)+(c-'0')*mul;
        c=getchar_unlocked();
    }
}

int main(void) {
	// your code goes here
	int t,n,k,i,j,c,z,p,fact[1000005];
	long long int l,r,arr[1000005],q,w;
	char a[1000005]={1,1};
	for(i=4;i*2<1000000;i+=2)
	    a[i]=1;
	for(i=3;i*i<1000000;i+=2){
	    if(a[i])
	        continue;
	    for(j=i*i;j<1000000;){
	        a[j]=1;
	        j+=2*i;
	    }
	}
	scani(&t);
	while(t--){
	    k=0;
	    scanf("%lld%lld",&l,&r);
	    if(l<2)
	        l=2;
	    for(w=l;w<=r;w++){
	        arr[w-l]=w;
	        fact[w-l]=1;
	    }
	    for(w=2;w*w<=r;w++){
	        if(a[w])
	            continue;
	        for(q=((l-1)/w+1)*w;q<=r;q+=w){
	            c=0;
	            p=q-l;
	            while(arr[p]%w==0){
	                arr[p]/=w;
	                c++;
	            }
	            fact[p]*=c+1;
	        }
	    }
	    for(i=0;i<=r-l;i++){
	        if(arr[i]>1){
	            fact[i]*=2;
	        }
	        if(a[fact[i]]==0)
	            k++;
	    }
	    printf("%d\n",k);
	}
	return 0;
}

Yet Another Cute Girl CodeChef Solution in JAVA

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//package kg.my_algorithms.codechef;



import jdk.jshell.spi.SPIResolutionException;

import java.io.*;
import java.util.*;
//       NO PROFILE CHECK     AND      Code of Conduct for Future Family
public class Main {
    private static final long MOD = 1_000_000_007L;
    public static void main(String[] args) throws IOException {
        BufferedWriter output = new BufferedWriter(new OutputStreamWriter(System.out));
        FastReader fr = new FastReader();
        StringBuilder sb = new StringBuilder();
        int testCases = fr.nextInt();
        HashSet<Integer> primes =new HashSet<>();
        int nn = 1_000_001;
        boolean[] visited = new boolean[nn+1];
        for(int i=2;i<=nn;i++){
            if(!visited[i]){
                primes.add(i);
                for(int j=i;j<=nn;j+=i) {
                    visited[j] = true;
                }
            }
        }
        for(int testCase=1;testCase<=testCases;testCase++){
            long left = fr.nextLong();
            long right = fr.nextLong();
            int n = (int)(right-left+1);
            int[] divisors = new int[n];
            int right_limit = (int)Math.sqrt(right);
            for(int i=1;i<=right_limit;i++){
                long start = ((long)Math.ceil(left/(double)i))*i;
                for(long j=start;j<=right;j+=i){
                    int pos = (int)(j-left);
                    divisors[pos]++;
                    long otherSide = j/i;
                    if(otherSide>right_limit) divisors[pos]++;
                }
            }
            int cnt = 0;
            for(int a: divisors) if(primes.contains(a)) cnt++;

 //           System.out.println("divisors= " + Arrays.toString(divisors));
            sb.append(cnt).append("\n");
        }
        output.write(sb.toString());
        output.flush();
    }


}









class FastReader {
    BufferedReader br;
    StringTokenizer st;

    public FastReader()
    {
        br = new BufferedReader(new InputStreamReader(System.in));
    }

    String next() {
        while (st == null || !st.hasMoreElements()) {
            try {
                st = new StringTokenizer(br.readLine());
            }
            catch (IOException e) {
                e.printStackTrace();
            }
        }
        return st.nextToken();
    }

    int nextInt() { return Integer.parseInt(next()); }

    long nextLong() { return Long.parseLong(next()); }

    double nextDouble()
    {
        return Double.parseDouble(next());
    }

    String nextLine()
    {
        String str = "";
        try {
            if(st.hasMoreTokens()){
                str = st.nextToken("\n");
            }
            else{
                str = br.readLine();
            }
        }
        catch (IOException e) {
            e.printStackTrace();
        }
        return str;
    }
}

Yet Another Cute Girl CodeChef Solution in PYPY 3

“ ”

from bisect import bisect
from math import sqrt,floor

prime = []
isprime = [True]*(10**6 + 2)

isprime[0] = False
isprime[1] = False

for x in range(2,10**6+2):
    if(isprime[x]):
        prime.append(x)
        for i in range(2*x,10**6+2,x):
            isprime[i] = False
# print(prime)
for _ in range(int(input())):
    a,b = map(int,input().split())
    sq_rt = floor(sqrt(b)) + 1
    index = bisect(prime,sq_rt)
    arr = prime[:index]
    ans = 0
    if(a<=1):
        a=2
    isprime = [True]*(b-a+1)
    for x in arr:
        st = floor(a/x)*x
        if(st<a):
            st+=x
        if(st==x):
            st+=x
        st = st-a
        for y in range(st,b-a+1,x):
            if(isprime[y]==True):
                isprime[y] = [x]
            else:
                isprime[y].append(x)
    for x in range(b-a+1):
        if(isprime[x]==True):
            ans+=1
        else:
            temp = 1
            val = a+x
            if(sqrt(val) == int(sqrt(val))):
                c = 0
                while(val>1 and c<len(isprime[x])):
                    elem = isprime[x][c]
                    t = 0
                    while(val%elem==0):
                        t+=1
                        val = val//elem
                    temp *= (1+t)
                    c+=1
                pos = bisect(prime,temp) - 1
    #             print(pos,ans,prime[pos])
                if(prime[pos]==temp):
                    ans+=1
            else:
                continue
#         print(ans)
    print(ans)

Yet Another Cute Girl CodeChef Solution in PYTH

“ ”

import bisect


def get_primes1(n=10**6):
    sieve =[True] * n
    for i in xrange(3, int(n**.5) + 1, 2):
        if sieve[i]:
            sieve[i*i::2*i] = [False] * ((n - i*i - 1) / (2*i) + 1)
    primes = [2] + [i for i in xrange(3, n, 2) if sieve[i]]

    primes_power = []
    max_ = 10 ** 12
    for p in primes:
        for e in primes:
            if e == 2:
                continue
            r = p ** (e - 1)
            if r > max_:
                break
            primes_power.append(r)
    return primes, sorted(primes_power)


PRIMES, PRIMES_POWER = get_primes1()
#print ">>> ", PRIMES[:10]
#print ">>> ", PRIMES_POWER[:10]

def get_primes2(a, b):
    max_ = 10 ** 6
    primes_count = 0
    i_p = bisect.bisect_left(PRIMES_POWER, a)
    j_p = bisect.bisect(PRIMES_POWER, b)
    primes_power_count = j_p - i_p

    # Case a or/and b are less than 10**6 is already computed.
    if a <= max_:
        i_p = bisect.bisect_left(PRIMES, a)
        a = max_ + 1
        if b <= max_:
            j_p = bisect.bisect(PRIMES, b)
            return j_p - i_p + primes_power_count
        else:
            primes_count = len(PRIMES) - i_p

    # Get primes between a and b.
    sieve = [True] * (b - a + 1)
    for p in PRIMES:
        if a % p == 0:
            i = a
        else:
            i = a + p - (a % p)
        sieve[i-a::p] = [False] * ((b - i) / p + 1)
    s = a
    while s <= b:
        primes_count += sieve[s-a]
        s += 1
    return primes_count + primes_power_count


def main():
    t = int(raw_input())
    for _ in xrange(t):
        a, b = map(int, raw_input().split())
        print get_primes2(a, b)


if __name__ == '__main__':
    main()

Yet Another Cute Girl CodeChef Solution in C#

“ ”

using System;

static class program
{
    public static void Main()
    {
        bool[] prime = new bool[1000001];
        prime[0] = prime[1] = false;
        int[] primes = new int[1000000];
        int pc = 0;
        for (int i = 2; i <= 1000000; ++i)
        {
            prime[i] = true;
        }
        for (int i = 2; i <= 1000000; ++i)
        {
            if (prime[i] == true)
            {
                primes[pc++] = i;
                for (int j = 2; i * j <= 1000000; ++j)
                {
                    prime[i * j] = false;
                }
            }
        }
        int t = int.Parse(Console.ReadLine());
        for (int i = 0; i < t; ++i)
        {
            long l, r;
            string[] ip = Console.ReadLine().Split();
            l = long.Parse(ip[0]);
            r = long.Parse(ip[1]);
            if (l == 1) ++l;
            long n = r - l + 1;
            bool[] segment = new bool[n];
            for (int j = 0; j < n; ++j)
            {
                segment[j] = true;
            }
            
            
                for (int k = 0; k < pc && primes[k]<=Math.Sqrt(r); ++k)
                {
                    long st = (long)Math.Ceiling(1.0 * l / primes[k]);
                    st *= primes[k];
                    if (st == 1 || primes[k] == st)
                    {
                        st += primes[k];
                    }
                    for (; st <= r; st += primes[k])
                    {
                        segment[st - l] = false;
                    }
           }
            
            int ans=0;
            for (int j = 0; j < n; ++j)
            {
                if (segment[j] == true) ++ans;
            }
            //Console.WriteLine(ans);
            for (int j = 0; primes[j] <= Math.Sqrt(r) && j<pc; ++j)
            {
                int sol1 = (int)(Math.Log(r)/Math.Log(primes[j]));
                int sol2 = (int)Math.Ceiling(Math.Log(l)/Math.Log(primes[j]));
                for (int k = sol2; k <= sol1; ++k)
                {
                    if (k >= 2 && prime[k + 1] == true) ++ans;
                }
            }
            Console.WriteLine(ans);
            //Console.ReadLine();
        }
    }
}

Yet Another Cute Girl CodeChef Solution in GO

“ ”

package main

import (
	"fmt"
	//"time"
)

const (
	max_prime = 100000
)
var sieve [max_prime]bool
var primes []int

func fill_sieve() {
	n := len(sieve)
	sieve[0] = true
	sieve[1] = true
	for i := 2; i * i < n; i++ {
		if sieve[i] {
			//i is not a prime
			continue
		}
		for j := i * i; j < n; j += i {
			sieve[j] = true
		}
	}
}

func append_primes() {
	for i, v := range sieve {
		if !v {
			primes = append(primes, i)
		}
	}
}

func prepare_primes() {
	fill_sieve()
	//append_primes()
}

func main() {
//	defer func(start time.Time) {
//		fmt.Println("Solution Time:", time.Since(start))
//	}(time.Now())

	prepare_primes()
	var interval [1000*1000 + 1]int
	for i := uint64(0); i < 1000*1000 + 1; i++ {
		interval[i] = 2
	}
	var T int
	fmt.Scan(&T)
	for ; T > 0; T-- {
		var a, b uint64
		fmt.Scan(&a)
		fmt.Scan(&b)
		if a == 1 {
			interval[0] = 1
		}
		for i := uint64(2); i * i <= b; i++ {
			i2 := i * i
			begin := a / i * i
			if begin < a {
				begin += i
			}
			if begin < i2 {
				begin = i2
			}
			for j := begin; j <= b; j += i {
				interval[j - a] += 2
				if j == i2 {
					interval[j - a]--
				}
			}
		}
		count := 0
		for i := uint64(0); i <= b - a; i++ {
			if !sieve[interval[i]] {
				count++
			}
			interval[i] = 2
		}
		fmt.Println(count)
	}
}

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