Zigzag Conversion LeetCode Solution

Problem – Zigzag Conversion LeetCode Solution

The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   N
A P L S I I G
Y   I   R

And then read line by line: "PAHNAPLSIIGYIR"

Write the code that will take a string and make this conversion given a number of rows:

string convert(string s, int numRows);

Example 1:

Input: s = "PAYPALISHIRING", numRows = 3
Output: "PAHNAPLSIIGYIR"

Example 2:

Input: s = "PAYPALISHIRING", numRows = 4
Output: "PINALSIGYAHRPI"
Explanation:
P     I    N
A   L S  I G
Y A   H R
P     I

Example 3:

Input: s = "A", numRows = 1
Output: "A"

Constraints:

• 1 <= s.length <= 1000
• s consists of English letters (lower-case and upper-case), ',' and '.'.
• 1 <= numRows <= 1000

Zigzag Conversion LeetCode Solution in Java

public String convert(String s, int nRows) {
    char[] c = s.toCharArray();
    int len = c.length;
    StringBuffer[] sb = new StringBuffer[nRows];
    for (int i = 0; i < sb.length; i++) sb[i] = new StringBuffer();
    
    int i = 0;
    while (i < len) {
        for (int idx = 0; idx < nRows && i < len; idx++) // vertically down
            sb[idx].append(c[i++]);
        for (int idx = nRows-2; idx >= 1 && i < len; idx--) // obliquely up
            sb[idx].append(c[i++]);
    }
    for (int idx = 1; idx < sb.length; idx++)
        sb[0].append(sb[idx]);
    return sb[0].toString();
}

Zigzag Conversion LeetCode Solution in Python

class Solution(object):
    def convert(self, s, numRows):
        """
        :type s: str
        :type numRows: int
        :rtype: str
        """
        if numRows == 1 or numRows >= len(s):
            return s

        L = [''] * numRows
        index, step = 0, 1

        for x in s:
            L[index] += x
            if index == 0:
                step = 1
            elif index == numRows -1:
                step = -1
            index += step

        return ''.join(L)

Zigzag Conversion LeetCode Solution in C++

string convert(string s, int nRows) {
    
    if (nRows <= 1)
        return s;

    const int len = (int)s.length();
    string *str = new string[nRows];

    int row = 0, step = 1;
    for (int i = 0; i < len; ++i)
    {
        str[row].push_back(s[i]);

        if (row == 0)
            step = 1;
        else if (row == nRows - 1)
            step = -1;

        row += step;
    }

    s.clear();
    for (int j = 0; j < nRows; ++j)
    {
        s.append(str[j]);
    }

    delete[] str;
    return s;
}

Zigzag Conversion LeetCode Solution in Swift

class Solution {
    func convert(_ s: String, _ numRows: Int) -> String {
        guard s.count > 1 && numRows > 1 else { return s }
        
        var lines = [[Character]](repeating: [], count: numRows)
        var idx = 0
        var flag = false
        
        for ch in s {
            lines[idx].append(ch)
            idx += flag ? -1 : 1
            guard idx == -1 || idx == numRows else { continue }
            idx += flag ? 2 : -2
            flag.toggle()
        }
        return lines.map { String($0) }.joined()
    }
}

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