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# Zipped in Hacker Rank Solution – Queslers

## Problem : Zipped Hacker Rank Solution

This function returns a list of tuples. The i th tuple contains the i th element from each of the argument sequences or iterables.
If the argument sequences are of unequal lengths, then the returned list is truncated to the length of the shortest argument sequence.
Sample Code :

``````>>> print zip([1,2,3,4,5,6],'Hacker')
[(1, 'H'), (2, 'a'), (3, 'c'), (4, 'k'), (5, 'e'), (6, 'r')]
>>>
>>> print zip([1,2,3,4,5,6],[0,9,8,7,6,5,4,3,2,1])
[(1, 0), (2, 9), (3, 8), (4, 7), (5, 6), (6, 5)]
>>>
>>> A = [1,2,3]
>>> B = [6,5,4]
>>> C = [7,8,9]
>>> X = [A] + [B] + [C]
>>>
>>> print zip(*X)
[(1, 6, 7), (2, 5, 8), (3, 4, 9)]
``````

The National University conducts an examination of  N students in X subjects.

The format for the general mark sheet is:

``````Student ID → ___1_____2_____3_____4_____5__
Subject 1   |  89    90    78    93    80
Subject 2   |  90    91    85    88    86
Subject 3   |  91    92    83    89    90.5
|______________________________
Average        90    91    82    90    85.5
``````

#### Input Format :

The first line contains N and X separated by a space.
The next X lines contains the space separated marks obtained by students in a particular subject.

• 0 < N <= 100
• 0 < X <= 100

#### Output Format :

Print the averages of all students on separate lines.
The averages must be correct up to 1 decimal place.

#### Sample Input :

``````5 3
89 90 78 93 80
90 91 85 88 86
91 92 83 89 90.5
``````

#### Sample Output :

``````90.0
91.0
82.0
90.0
85.5
``````

#### Explanation :

Marks obtained by student 1: 89 90 91
Average marks of student 1:
270 / 3 = 90.0
Marks obtained by student 2: 90 91 92
Average marks of student 2:
273 / 3 = 91.0
Marks obtained by student 3: 78 85 83
Average marks of student 3:
246 / 3 = 82.0
Marks obtained by student 4: 93 88 89
Average marks of student 4:
270 / 3 = 90.0
Marks obtained by student 5: 80 86 90.5
Average marks of student 5:256.5 / 3 = 85.5

### Zipped Hacker Rank Solution in python 2

``````N,X = map(int,raw_input().split())
marks = []

for i in xrange(X):
marks.append(map(float,raw_input().split()))

for studentScores in zip(*marks):
print sum(studentScores)/len(studentScores)``````

### Zipped Hacker Rank Solution in python 3

``````# Enter your code here. Read input from STDIN. Print output to STDOUT
n, x = map(int, input().split())

sheet = []
for _ in range(x):
sheet.append( map(float, input().split()) )

for i in zip(*sheet):
print( sum(i)/len(i) )
``````

### Zipped Hacker Rank Solution in pypy

``````# Enter your code here. Read input from STDIN. Print output to STDOUT
n, x = map(int, raw_input().split())
all_scores = [map(float, raw_input().split()) for _ in xrange(x)]

for student, score in zip(range(1, n+1), zip(*all_scores)):
print sum(score)/x``````

### Zipped Hacker Rank Solution in pypy 3

``````# Enter your code here. Read input from STDIN. Print output to STDOUT
# Enter your code here. Read input from STDIN. Print output to STDOUT
num_of_std,num_of_sbj=map(int,input().split())

all_scores=[]
for _ in range(num_of_sbj):
all_scores.append(map(float,input().split()))

scores_by_std=zip(*all_scores)
avg_scores_by_std=[sum(scores)/num_of_sbj for scores in scores_by_std]
for avg_score in avg_scores_by_std:
print(avg_score)``````
##### Zipped Hacker Rank Solution Review:

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##### Zipped Hacker Rank Solution Conclusion:

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